Question

如何使用mu openweather API处理地理位置？这是我目前的HTML代码：

<!DOCTYPE html>
<html>
    <head>
        <link rel="stylesheet" href="http://s3.amazonaws.com/codecademy-content/courses/ltp/css/bootstrap.css">
        <link rel="stylesheet" href="main.css">
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
        <script type='text/javascript' src='app.js'></script>
    </head>
    <body>
        <div class="jumbotron">
            <button onclick="getLocation()">Get my location.</button>
            <p id="demo"></p>

            <script>
                var x = document.getElementById("demo");
                function getLocation() {
                    if (navigator.geolocation) {
                        navigator.geolocation.getCurrentPosition(showPosition);
                    } else { 
                        x.innerHTML = "Geolocation is not supported by this browser.";
                    }
                }

                function showPosition(position) {
                    x.innerHTML = "Latitude: " + position.coords.latitude + 
                                  "<br>Longitude: " + position.coords.longitude;    
                }
            </script>

            <p>The weather outside is: </p> 
            <div class= "weather">
                Oops.. there is no temperature available for your location right now.
            </div>
        </div>                                  
    </body>
</html>

我的JavaScript代码：

$(document).ready(function(){
    $.getJSON( "http://api.openweathermap.org/data/2.5/weather?q=Eindhoven&appid=9334f947893792dcb9b2e2c05ae23eb0", function( data ) {
        $('.weather').html(Math.round(data.main.temp-273)+ ' degrees Celcius');
    });

});

我在埃因霍温市的天气工作，但我希望能够调整到纬度和经度。有人可以为我修复我的代码吗？帮助我？

我知道这与此链接有关：api.openweathermap.org/data/2.5/weather?lat={lat}&lon={lon}但我不知道如何实施我的拥有其中的经度和经度...

Answer 1

您可以使用第三方API获取有关该位置的数据，例如：http://ip-api.com/

var getIP = 'http://ip-api.com/json/';
$.getJSON(getIP).done(function(location) {
    console.log(location)
})

接下来使用我们上面提到的ip-api从OpenWeatherMap服务获取WeatherData

var getIP = 'http://ip-api.com/json/';
var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
$.getJSON(getIP).done(function(location) {
    $.getJSON(openWeatherMap, {
        lat: location.lat,
        lon: location.lon,
        units: 'metric',
        APPID: 'APIKEY'
    }).done(function(weather) {
        console.log(weather)
    })
})

在这种情况下，摄氏温度（公制）

或使用HTML5地理位置API（在Google Chrome中仅与HTTPS或localhost合作）

var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
if (window.navigator && window.navigator.geolocation) {
    window.navigator.geolocation.getCurrentPosition(function(position) {
        $.getJSON(openWeatherMap, {
            lat: position.coords.latitude,
            lon: position.coords.longitude,
            units: 'metric',
            APPID: 'APIKEY'
        }).done(function(weather) {
            console.log(weather)
        })
    })
}

Answer 2

让我们尝试一下，我希望这是通过使用geolacation和Openweather API获取当前天气的更好解决方案。只需传递您的Openweather API密钥，您将获得一个json数组，获取您的位置和当前天气。而且，您还可以使用所需的天气图标。

window.addEventListener("load",() =>{
    let long;
    let lag;
    
    if(navigator.geolocation){
        navigator.geolocation.getCurrentPosition((position) =>{
        var lat = position.coords.latitude;
        var long = position.coords.longitude;
        const proxy = "https://cors-anywhere.herokuapp.com/";
        const api = `${proxy}api.openweathermap.org/data/2.5/weather?lat=${lat}&lon=${long}&appid=9891731b361e47661f72b06213efbf65`;
        fetch(api) 
           .then((response) =>{
               return response.json();
           })
           .then(data =>{
               const {name} = data;
               const {feels_like} = data.main;
               const {id,main} = data.weather[0];
               loc.textContent = name;
               climate.textContent = main;
               tempValue.textContent = Math.round(feels_like-273);
               if(id < 250){
                   tempIcon.src = './icon/storm.svg'
               } 
               else if(id < 350){
                tempIcon.src = './icon/drizzle.svg'  
               }
               else if(id < 550){
                tempIcon.src = './icon/rain.svg'  
               }
               else if(id < 650){
                tempIcon.src = './icon/snow.svg'  
               }
               else if(id < 800){
                tempIcon.src = './icon/atmosphere.svg'  
               }
               else if(id === 800){
                tempIcon.src = './icon/clear.svg'  
               }
               else if(id >800){
                tempIcon.src = './icon/clouds.svg'  
               }
               console.log(data);
           })
        })  
    }
})

如何在openweather API中获取地理位置

2 个答案: