Question

我正在尝试创建一个用户系统，但是有一部分代码无法执行。我正在使用ajax将值传递给PHP，但是这个块只是没有执行，我不明白为什么。

PHP

<?
/* New Follower */
include_once("php/check_user_log.php");
include_once("php/db_conx.php");
if(isset($_POST["follower"])){
echo "success_1";
if ($_POST["follower"] == "yes"){
    echo "success_2";
    $follower_id = $log_id;
    $following_id = $_GET["u"];
    echo "success_3";

    $curr_followers = $followers;
    $new_followers = $curr_followers.",".$follower_id;
    echo "success_4";

    $follower_update = "UPDATE users SET followers='$new_followers' WHERE username=$following_id";
    $query = mysqli_query($db_conx, $follower_update);
    echo "success_5";

    $follower_sql = "SELECT * FROM users WHERE id='$log_id' AND activated='1' LIMIT 1";
    $follower_query = mysqli_query($db_conx, $follower_sql);
    echo "success_6";

    while ($row = mysqli_fetch_array($follower_query, MYSQLI_ASSOC)) {
        $follower_following = $row["following"];
    }
    echo "success_7";

    $curr_following = $follower_following;
    $new_following = $curr_following.",".$following_id;
    echo "success_8";

    $following_update = "UPDATE users SET following='$new_following' WHERE id=$log_id";
    $query1 = mysqli_query($db_conx, $following_update);

    echo "success_9";
} else {
    echo "fail_1";
    exit();
}
}
/* End New Follower */
?>

的Javascript

function newFollower(){
            var new_follower = "yes";
            if(new_follower == ""){
                $(".logo").html("new_follower not set");
            } else {
                var ajax = ajaxObj("POST", "profile.php");
                ajax.onreadystatechange = function() {
                    if(ajaxReturn(ajax) == true) {
                        if (ajax.responseText == "success_1"){
                            $(".logo").html("success_1");
                        } else if (ajax.responseText == "success_2"){
                            $(".logo").html("success_2");
                        } else if (ajax.responseText == "success_3"){
                            $(".logo").html("success_3");
                        } else if (ajax.responseText == "success_4"){
                            $(".logo").html("success_4");
                        } else if (ajax.responseText == "success_5"){
                            $(".logo").html("success_5");
                        } else if (ajax.responseText == "success_6"){
                            $(".logo").html("success_6");
                        } else if (ajax.responseText == "success_7"){
                            $(".logo").html("success_7");
                        } else if (ajax.responseText == "success_8"){
                            $(".logo").html("success_8");
                        } else if (ajax.responseText == "success_9"){
                            $(".logo").html("success_9");
                        } else if (ajax.responseText == "fail_1"){
                            $(".logo").html("fail_1");
                        } else if (ajax.responseText == "fail_2"){
                            $(".logo").html("fail_2");
                        } else {
                            $(".logo").html("unknown error");
                        }
                    }
                }
                ajax.send("follower="+new_follower);
            }
        }

如果您还想知道其他任何事情，请问我不完全确定您需要哪些信息。

Answer 1

谢谢肖恩。您对ajax打开页面profile.php的评论不是当前页面的问题。

PHP代码不会执行

1 个答案: