Visual Studio将类方法解释为静态,但它们不是。当我构建下面的代码时,我有110个错误。
错误:Foto with errors 1.,Foto with errors 2.
这可能是错误的声明这些方法吗?
//header
class Player {
public:
Player(int x, int y) {
PlayerX = x;
PlayerY = y;
};
void doAction(int input, Mapa *mapa);
int getDirection();
Vector2 getPosition();
int
PlayerX, PlayerY, direction;
void turn(int dir);
void move(int move, Vector2 mapSize, Mapa *mapa);
Vector2 getCordInFrontOfCharacter();
Vector2 getCordBehindCharacter();
};
和cpp文件:
#include "Vector2.h"
#include "Player.h"
#include "Mapa.h"
using namespace std;
int PlayerX = 0, PlayerY = 0;
int direction = 0;
void Player::doAction(int input, Mapa *mapa) {
if (input == (char)72)
this->move(1, *mapa->mapSize, mapa);
else if (input == (char)80)
this->move(-1, *mapa->mapSize, mapa);
if (input == (char)75)
this->turn(-1);
else if (input == (char)77)
this->turn(1);
}
void Player::turn(int dir) {
if (dir < 0)
dir = 2 - dir;
direction = (direction + dir) % 4;
}
void Player::move(int move, Vector2 mapSize, Mapa *mapa) {
if (
move = 1
&& getCordInFrontOfCharacter().y - 1 >= 0
&& getCordInFrontOfCharacter().x - 1 >= 0
&& getCordInFrontOfCharacter().y - 1 < mapSize.y
&& getCordInFrontOfCharacter().x - 1 < mapSize.x
&& mapa->_Mapa[getCordInFrontOfCharacter().y - 1][getCordInFrontOfCharacter().x - 1] == '0') {
if (this->direction == 0)
this->PlayerY -= move;
else if (this->direction == 2)
this->PlayerY += move;
else if (this->direction == 1)
this->PlayerX += move;
else if (this->direction == 3)
this->PlayerX -= move;
if (this->PlayerY < 1)
this->PlayerY = 1;
if (this->PlayerX < 1)
this->PlayerX = 1;
if (this->PlayerY > mapSize.y)
this->PlayerY = mapSize.y;
if (this->PlayerX > mapSize.x)
this->PlayerX = mapSize.x;
}
else if (
move = 1
&& this->getCordBehindCharacter().y - 1 >= 0
&& this->getCordBehindCharacter().x - 1 >= 0
&& this->getCordBehindCharacter().y - 1 < mapSize.y
&& this->getCordBehindCharacter().x - 1 < mapSize.x
&& mapa->_Mapa[this->getCordBehindCharacter().y - 1][this->getCordBehindCharacter().x - 1] == '0') {
if (this->direction == 0)
this->PlayerY -= move;
else if (this->direction == 2)
this->PlayerY += move;
else if (this->direction == 1)
this->PlayerX += move;
else if (this->direction == 3)
this->PlayerX -= move;
if (this->PlayerY < 1)
this->PlayerY = 1;
if (this->PlayerX < 1)
this->PlayerX = 1;
if (this->PlayerY > mapSize.y)
this->PlayerY = mapSize.y;
if (this->PlayerX > mapSize.x)
this->PlayerX = mapSize.x;
}
}
int Player::getDirection() {
return this->direction;
}
Vector2 Player::getPosition() {
return Vector2(this->PlayerX, this->PlayerY);
}
Vector2 Player::getCordInFrontOfCharacter() {
if (this->direction == 2)
return Vector2(this->PlayerX, this->PlayerY + 1);
else if (this->direction == 0)
return Vector2(this->PlayerX, this->PlayerY - 1);
else if (this->direction == 3)
return Vector2(this->PlayerX - 1, this->PlayerY);
else if (this->direction == 1)
return Vector2(this->PlayerX + 1, this->PlayerY);
return Vector2(0, 0);
}
Vector2 Player::getCordBehindCharacter() {
if (direction == 2)
return Vector2(this->PlayerX, this->PlayerY - 1);
else if (this->direction == 0)
return Vector2(this->PlayerX, this->PlayerY + 1);
else if (this->direction == 3)
return Vector2(this->PlayerX + 1, this->PlayerY);
else if (this->direction == 1)
return Vector2(this->PlayerX - 1, this->PlayerY);
return Vector2(0, 0);
}
感谢您的帮助。
答案 0 :(得分:0)
在cpp文件中,我使用&#34; ::&#34;
初始化非静态方法
在c ++中初始化方法几乎是不可能的。我是你的班级成员,那么,那是错的。
如果您有非静态成员,则无法执行此操作:
int foo::member = 0; // error, member is non-static
每个foo对象都有自己的int member
,所以它们之间没有共享。您必须为构造函数中的每个对象设置它(可能是您要查找的默认值):
foo::foo (int _mem = 0, ... ) : member(_mem) {...}
答案 1 :(得分:0)
Visual Studio编译器显然对此函数签名感到困惑
void Player::move(int move, Vector2 mapSize, Mapa *mapa)
其中相同的名称用于参数和函数本身。 改变它以使它们区别开来:
void Player::move(int move_, Vector2 mapSize, Mapa *mapa)
// ^