Question

我正在使用带有QT和python复选框的GUI，当选中该复选框时，我想显示＆＃39; stackoverflow＆＃39;每隔5秒，当它被取消选中时，我希望它什么都不做。我在检查时尝试调用以下函数：

def work (): 
    threading.Timer(5, work).start ()
    print "stackoverflow"

def checkbox(self, state):
    if state == QtCore.Qt.Checked:
        print 'checked'
        work()
    else: print 'unchecked'

但它继续印刷＆＃39; stackoverflow＆＃39;。我怎么能阻止这个？

Answer 1

这是一个解决方案。

from threading import Thread
import time

class WorkerThread:

    def __init__(self, timer=5):
        self.timer = timer
        self._alive = False

    def work(self):
        while self._alive:
            time.sleep(self.timer)
            print("Stack Overflow")

    def start(self):
        self._thread = Thread(target=self.work)
        self._alive = True
        self._thread.start()

    def stop(self):
        self._alive = False

worker_thread = WorkerThread()

def checkbox(self, state):
    if state == QtCore.Qt.Checked:
        worker_thread.start()
    else:
        worker_thread.stop()

Answer 2

您可以使用变量来控制线程

running = False

def work (): 
    print "stackoverflow"
    if running:
        threading.Timer(5, work).start ()

def checkbox(self, state):
    global running

    if state == QtCore.Qt.Checked:
        print 'checked'
        running = True
        work()
    else: 
        print 'unchecked'
        running = False

如何使用GUI停止python线程脚本

2 个答案: