Question

我有几列，我正在寻找一个SQL查询，它可以为我提供第4列和第5列的输出，当第一次看到值时，我的值为1，当它再次出现时，值将为0。

希望我的问题不是很复杂。

UniqueNameCount和UniqueDESCCount是我正在看的输出......

Inventory ID    Name    Description UniqueNameCount UniqueDESCCount

预期结果：

Inventory ID    Name    Description UniqueNameCount UniqueDESCCount
IN0001  Item 1  Desc 1  1   1
IN0002  Item 2  Desc 2  1   1
IN0003  Item 3  Desc 1  1   0
IN0004  Item 1  Desc 1  0   0
IN0005  Item 2  Desc 5  0   1
IN0006  Item 2  Desc 5  0   0
IN0007  Item 2  Desc 5  0   0
IN0008  Item 3  Desc 2  0   0
IN0009  Item 3  Desc 2  0   0
IN0010  Item 1  Desc 3  0   1

Answer 1

使用相关的子查询来确定是否为较低的Inventory_ID查看了相同的名称或描述。

ON_COMMAND

可替换地：

select Inventory_ID, Name, Description,
       case when exists (select 1 from tablename t2
                         where t2.Name = t1.name
                           and t2.Inventory_ID < t1.Inventory_ID) then 0
            else 1
       end as UniqueNameCount,
       case when exists (select 1 from tablename t2
                         where t2.Description= t1.Description
                           and t2.Inventory_ID < t1.Inventory_ID) then 0
            else 1
       end as UniqueDESCCount
from tablename t1

Answer 2

SQL Fiddle

Oracle 11g R2架构设置：

CREATE TABLE table_name ( Inventory_ID, Name, Description ) AS
          SELECT 'IN0001',  'Item 1',  'Desc 1' FROM DUAL
UNION ALL SELECT 'IN0002',  'Item 2',  'Desc 2' FROM DUAL
UNION ALL SELECT 'IN0003',  'Item 3',  'Desc 1' FROM DUAL
UNION ALL SELECT 'IN0004',  'Item 1',  'Desc 1' FROM DUAL
UNION ALL SELECT 'IN0005',  'Item 2',  'Desc 5' FROM DUAL
UNION ALL SELECT 'IN0006',  'Item 2',  'Desc 5' FROM DUAL
UNION ALL SELECT 'IN0007',  'Item 2',  'Desc 5' FROM DUAL
UNION ALL SELECT 'IN0008',  'Item 3',  'Desc 2' FROM DUAL
UNION ALL SELECT 'IN0009',  'Item 3',  'Desc 2' FROM DUAL
UNION ALL SELECT 'IN0010',  'Item 1',  'Desc 3' FROM DUAL;

查询1 ：

SELECT Inventory_ID,
       Name,
       Description,
       CASE
         WHEN LAG( Name ) OVER ( PARTITION BY Name ORDER BY Inventory_ID ) IS NULL
         THEN 1
         ELSE 0
         END AS UniqueNameCount,
       CASE
         WHEN LAG( Description ) OVER ( PARTITION BY Description ORDER BY Inventory_ID ) IS NULL
         THEN 1
         ELSE 0
         END AS UniqueDESCCount
FROM   table_name
ORDER BY Inventory_ID

<强> Results ：

| INVENTORY_ID |   NAME | DESCRIPTION | UNIQUENAMECOUNT | UNIQUEDESCCOUNT |
|--------------|--------|-------------|-----------------|-----------------|
|       IN0001 | Item 1 |      Desc 1 |               1 |               1 |
|       IN0002 | Item 2 |      Desc 2 |               1 |               1 |
|       IN0003 | Item 3 |      Desc 1 |               1 |               0 |
|       IN0004 | Item 1 |      Desc 1 |               0 |               0 |
|       IN0005 | Item 2 |      Desc 5 |               0 |               1 |
|       IN0006 | Item 2 |      Desc 5 |               0 |               0 |
|       IN0007 | Item 2 |      Desc 5 |               0 |               0 |
|       IN0008 | Item 3 |      Desc 2 |               0 |               0 |
|       IN0009 | Item 3 |      Desc 2 |               0 |               0 |
|       IN0010 | Item 1 |      Desc 3 |               0 |               1 |

如何在表格中首先找到记录，我有多个这样的记录

2 个答案: