如何在yii中知道表格提交成功

Question

我希望在表单提交成功时提交按钮禁用，因为用户点击提交按钮这么多次页面加载所以它保存了相同的记录这么多次。所以我想决定当表单提交成功意味着禁用提交按钮.i我也使用了aftervalidate函数，但它无法正确表单提交成功。

我的编码：

 <?php
 $form = $this->beginWidget('CActiveForm', array(
     'id' => 'question-form',
     // Please note: When you enable ajax validation, make sure the corresponding
     // controller action is handling ajax validation correctly.
     // There is a call to performAjaxValidation() commented in generated controller code.
     // See class documentation of CActiveForm for details on this.
     'enableAjaxValidation' => true,
     'enableClientValidation' => false,
     'clientOptions' => array(
         'validateOnSubmit' => true,
         'validateOnChange' => false,
         'afterValidate' => 'js:buttondisable',

     ),
 ));
 ?>
 <div class="form-group">
     <?php echo $form->labelEx($model, 'question_title'); ?>
     <?php echo $form->textField($model, 'question_title', array('size' => 50, 'maxlength' => 250, 'class' => 'form-control')); ?>
     <?php echo $form->error($model, 'question_title'); ?>
 </div>
 <?php if ($tileAssigned == Yii::app()->const->FLAG_ZERO) { ?>
 <div class="form-group">
     <?php echo $form->labelEx($model, 'type', array('label' => 'Is Multiple Choice')); ?>
     <?php echo $form->radioButtonList($model, 'type', $yesnoList, array('separator' => '', 'onchange' => 'questionTypeChange(this.value);', 'class' => '')); ?>
     <?php echo $form->error($model, 'type'); ?>
 </div>

但是在每次验证完成后验证函数调用之后，但是我想在此时成功提交提交禁用按钮。