Question

我正在使用Django Rest Framework的HyperlinkedModelSerializer，ModelViewset和DefaultRouter，最终得到如下的好网址：http://localhost:8000/api/users/1。我想，给定一个用户ID，找到该用户的完全限定的URL，而无需硬编码。给定53，我想要http://localhost:8000/api/users/1，当我转向生产时主机应该改变。

# from urls.py
router = routers.DefaultRouter()
router.register(r'users', shared_views.UserViewSet)


# from models.py
class UserViewSet(viewsets.ModelViewSet):
    '''
    endpoint for viewing/editing users
    '''
    queryset = User.objects.all().order_by('-date_joined')
    serializer_class = UserSerializer


# from serializers.py

class UserSerializer(serializers.HyperlinkedModelSerializer):
    class Meta:
        model = User
        fields = ('url', 'username', 'email', 'groups')

我该怎么做？我试过：reverse(UserViewSet.as_view({'get': 'retrieve'}), args=[request.user.id])但是出现了这个错误：

反向'shared.views.UserViewSet'，参数'（1，）'和关键字参数'{}'未找到。尝试了0种模式：[]

Answer 1

正如@Anush所说，我可以使用序列化程序来获取URL。请求需要以特定方式作为关键字参数传递（参见下文）：

class OwnedViewSet(viewsets.ModelViewSet):
    ''' ModelViewSets that use hyperlinked model serializers
        can inherit this to automatically
        set `owner` = current user. 
    '''
    def create(self, request, *args, **kwargs):
        serialized_owner = UserSerializer(request.user, context={'request': request})
        request.data['owner'] = serialized_owner.data['url']
        return super(OwnedViewSet, self).create(request, *args, **kwargs)

Django Rest Framework：查找超链接模型的URL

1 个答案: