Question

我试图将位于_name中的字符数组传递给名为name的char引用。

但是，当将数组指针传递给引用时，它只显示第一个字符而不是整个字符串。

我的问题是你如何创建一个Character引用数组来将原始指针复制到它然后显示它？如item.cpp中所示，我们将_name指针复制到name的引用中，然后返回name，但它只显示字符串的第一个字符。

我只会显示我的代码的相关部分。

输出：

456: **A**
Qty: 0
Cost (price * tax): 200.00
567: **B**
Qty: 50
Cost (price * tax): 300.00

Enter Item info for A: (Enter 123 for sku)
sku: 123
name (no spaces): andrew
qty: 5
is taxed? (1/0): 1
price: 15
Copying A in C ----
123: a
Qty: 5
Cost (price * tax): 200.00

Saving A---------
Loading B----------
A: ----------
123: a
Qty: 5
Cost (price * tax): 200.00

B: ----------
123: a
Qty: 5
Cost (price * tax): 300.00

C=B; op=----------
123: a
Qty: 5
Cost (price * tax): 300.00

Operator ==----------
op== is NOT OK

op+=: A += 20----------
123
123: a
Qty: 5
Cost (price * tax): 200.00

op-=: A -= 10----------
123
123: a
Qty: 5
Cost (price * tax): 200.00

op+=double: ----------
1000.00=0.00

注意它是如何切断我的名字（andrew）并只显示一个？

Item.cpp：

void Item::name(const char * name){

        strncpy(_name, name , 20);
}
const char& Item::name() const{
        char& name = *_name;
        return name;
}

ItemTester.cpp：

主（）：

int main(){
  double res, val = 0.0;
  fstream F;
  SItem Empty;
  SItem A("456", "AItem", 200);
  SItem B("567", "BItem", 300, false);
  //cout << A.name() << endl;
  B.quantity(50);
  //cout << Empty << endl;
  cout << A << endl << B << endl << endl;
  cout << "Enter Item info for A: (Enter 123 for sku)" << endl;
  cin >> A;

  cout << "Copying A in C ----" << endl;
  SItem C = A;
  cout << C << endl << endl;
  cout << "Saving A---------" << endl;
  A.save(F);
  cout << "Loading B----------" << endl;
  B.load(F);
  cout << "A: ----------" << endl;
  cout << A << endl << endl;
  cout << "B: ----------" << endl;
  cout << B << endl << endl;
  cout << "C=B; op=----------" << endl;
  C = B;
  cout << C << endl << endl;;
  cout << "Operator ==----------" << endl;
  cout << "op== is " << ((A == "123") && !(A == "234") ? "OK" : "NOT OK") << endl << endl;
  cout << "op+=: A += 20----------" << endl;
  A += 20;
  cout << A << endl << endl;
  cout << "op-=: A -= 10----------" << endl;
  A -= 10;
  cout << A << endl << endl;
  cout << "op+=double: ----------" << endl;
  res = val += A;
  cout << res << "=" << val << endl << endl;
  return 0;
}

ostream写

virtual std::ostream& write(std::ostream& os, bool linear)const{

     return os << sku() << ": " << name() << endl
       << "Qty: " << quantity() << endl
       << "Cost (price * tax): " << fixed << setprecision(2) << cost();
    }

如果我错过了任何重要的细节并且用它来编辑我的帖子，请告诉我。

char引用传递数组c ++

0 个答案: