sklearn:用户定义的时间序列数据交叉验证

时间:2015-11-25 23:20:51

标签: python scikit-learn cross-validation

我正在尝试解决机器学习问题。我有一个带有时间序列元素的特定数据集。对于这个问题,我使用着名的python库 - sklearn。这个库中有很多交叉验证迭代器。还有几个迭代器可以自己定义交叉验证。问题是我真的不知道如何为时间序列定义简单的交叉验证。这是我想要得到的一个很好的例子:

假设我们有几个句点(年),我们想将我们的数据集分成几个块,如下所示:

data = [1, 2, 3, 4, 5, 6, 7]

train: [1]                test: [2] (or test: [2, 3, 4, 5, 6, 7])
train: [1, 2]             test: [3] (or test: [3, 4, 5, 6, 7])
train: [1, 2, 3]          test: [4] (or test: [4, 5, 6, 7])
...
train: [1, 2, 3, 4, 5, 6] test: [7]

我无法真正理解如何使用sklearn工具创建这种交叉验证。可能我应该使用PredefinedSplit中的sklearn.cross_validation

train_fraction  = 0.8
train_size      = int(train_fraction * X_train.shape[0])
validation_size = X_train.shape[0] - train_size

cv_split = cross_validation.PredefinedSplit(test_fold=[-1] * train_size + [1] * validation_size)

结果:

train: [1, 2, 3, 4, 5] test: [6, 7]

但它仍然不如之前的数据分割

2 个答案:

答案 0 :(得分:6)

您可以在不使用sklearn的情况下获得所需的交叉验证拆分。这是一个例子

import numpy as np

from sklearn.svm import SVR
from sklearn.feature_selection import RFECV

# Generate some data.
N = 10
X_train = np.random.randn(N, 3)
y_train = np.random.randn(N)

# Define the splits.
idxs = np.arange(N)
cv_splits = [(idxs[:i], idxs[i:]) for i in range(1, N)]

# Create the RFE object and compute a cross-validated score.
svr = SVR(kernel="linear")
rfecv = RFECV(estimator=svr, step=1, cv=cv_splits)
rfecv.fit(X_train, y_train)

答案 1 :(得分:4)

同时,这已被添加到库中:http://scikit-learn.org/stable/modules/cross_validation.html#time-series-split

doc:

中的示例
>>> from sklearn.model_selection import TimeSeriesSplit

>>> X = np.array([[1, 2], [3, 4], [1, 2], [3, 4], [1, 2], [3, 4]])
>>> y = np.array([1, 2, 3, 4, 5, 6])
>>> tscv = TimeSeriesSplit(n_splits=3)
>>> print(tscv)  
TimeSeriesSplit(n_splits=3)
>>> for train, test in tscv.split(X):
...     print("%s %s" % (train, test))
[0 1 2] [3]
[0 1 2 3] [4]
[0 1 2 3 4] [5]