Question

我正在尝试编写替换这些max和min nubmers的代码然后再打印新的2d数组？

  public static void main(String[] args) {


    Scanner input = new Scanner(System.in);
    System.out.print("Unesite velicinu n niza:");
    int n = input.nextInt();

    System.out.print("Unesite velicinu m niza:");
    int m = input.nextInt();

    int [][] niz = new int [n][m];
    int max = niz[0][0];

    for (int i =0;i<niz.length;i++){
        for (int j = 0;j<niz[i].length;j++) {
            niz [i][j] = (int) (Math.random()*50);
            System.out.print(niz [i][j] + " ");
            if (niz [i][j] > max){
                max = niz [i][j];
            }
        }
        System.out.println(); 
    }
    System.out.println("Najveci broj je: " + max);

    int min = niz [0][0];

    for (int i =0;i<niz.length;i++){
        for (int j = 0;j<niz[i].length;j++) {
            if (niz [i][j]<min){
                min = niz[i][j];
            }
        }
    }
    System.out.println("Najmanji broj je: " + min);

Answer 1

您可以在初始数组中确定min和max（我分别使用Math.min(int, int)和Math.max(int, int)）。像

这样的东西

int max = Integer.MIN_VALUE;
int min = Integer.MAX_VALUE;
int [][] niz = new int [n][m];
for (int i =0;i<niz.length;i++){
    for (int j = 0;j<niz[i].length;j++) {
        niz [i][j] = (int) (Math.random()*50);
        System.out.print(niz [i][j] + " ");
        max = Math.max(max, niz[i][j]);
        min = Math.min(min, niz[i][j]);
    }
    System.out.println(); 
}

然后你可以用另一个循环交换min和max（和显示）。像

for (int i =0;i<niz.length;i++){
    for (int j = 0;j<niz[i].length;j++) {
        if (niz[i][j] == max) {
            niz[i][j] = min;
        } else if (niz[i][j] == min) {
            niz[i][j] = max;
        }
        System.out.print(niz [i][j] + " ");
    }
    System.out.println(); 
}

在2d array.Java中用最小数字替换最大数量

1 个答案: