Question

我正在尝试使用Python的zipfile模块在我的脚本中解压缩zip文件。问题是，当我尝试解压缩此文件时，它会引发Bad magic number for file header error：

这是error：

..
  zip_ref.extractall(destination_to_unzip_file)
  File "C:\Python27\lib\zipfile.py", line 1040, in extractall
    self.extract(zipinfo, path, pwd)
  File "C:\Python27\lib\zipfile.py", line 1028, in extract
    return self._extract_member(member, path, pwd)
  File "C:\Python27\lib\zipfile.py", line 1082, in _extract_member
    with self.open(member, pwd=pwd) as source, \
  File "C:\Python27\lib\zipfile.py", line 971, in open
    raise BadZipfile("Bad magic number for file header")
zipfile.BadZipfile: Bad magic number for file header

我想解压缩的文件是这样下载的：

_url = """http://edane.drsr.sk/report/ds_dphs_csv.zip"""

def download_platici_dph(self):
    if os.path.isfile(_destination_for_downloads+'platici_dph.zip'):
        os.remove(_destination_for_downloads+'platici_dph.zip')
    with open(_destination_for_downloads+'platici_dph.zip','w') as f:
        response = requests.get(_url,stream=True)
        if not response.ok:
            print 'Something went wrong'
            return False
        else:
            for block in response.iter_content(1024):
                f.write(block)

有谁知道问题出在哪里？

Answer 1

Quoth the documentation for open()：＆＃34; 打开二进制文件时，应将'b'附加到模式值以二进制模式打开文件＆＃34;

使用b为二进制文件打开输出文件：

with open(_destination_for_downloads+'platici_dph.zip','wb') as f:

Answer 2

我尝试下载您的存档而不使用您的下载代码，然后使用以下代码解压缩

import zipfile
with zipfile.ZipFile("ds_dphs_csv.zip") as a:
        a.extractall()

工作得很好。当标题出现问题时会引发异常 zipfile.BadZipfile ，因此我认为您的文件在下载后已损坏。您的下载方法一定存在问题。

您可以在此帖中找到有关例外的更多详细信息：Python - Extracting files from a large (6GB+) zip file

无法解压缩zip文件

2 个答案: