Ok过去几天一直在努力学习SQL到XML,这是我迄今为止能够自学的。
`SELECT distinct StudentItem.foldername AS "foldername", StudentItem.status, StudentItem.vhrid, StudentItem.firstname, StudentItem.middleinitial, StudentItem.lastname,
dbo.getEnumDescript(StudentType, 'StudentType') AS title,
StudentItem.email,
dbo.getEnumDescript(OfficeLocation, 'OfficeLocation') AS Office,
practices.id as 'StudentItem/practices/practice/id',
practices.name as 'StudentItem/practices/practice/name',
schoolItem.Name as 'StudentItem/bio/schools/schoolItem/schoolname',
schoolItem.schoolYear as 'lawyerItem/bio/schools/schoolItem/schoolyear'
FROM [dbo].[Student] as lawyerItem
LEFT JOIN [dbo].[StudentGroups] as aprac on StudentItem.vhrid = aprac.vhrid
INNER JOIN [dbo].[PracticeGroups] as practices on aprac.PracticeGroupID = practices.ID
LEFT JOIN [dbo].[StudentEducation] as schoolItem on StudentItem.vhrid = schoolItem.vhrid
where StudentItem.vhrid='50330'
FOR XML path, ROOT ('StudentItem'), ELEMENTS;`
我得到的是这个
`<StudentItems>
<row>
<foldername>susan.wissink</foldername>
<status>1</status>
<vhrid>50330</vhrid>
<firstname>Susan</firstname>
<middleinitial>M.</middleinitial>
<lastname>Wissink</lastname>
<title>Student leader</title>
<email>swissink@blank.com</email>
<Office>Phoenix</Office>
<StudentItem>
<practices>
<practice>
<id>681</id>
<name>Real Estate Finance and Lending</name>
</practice>
</practices>
<bio>
<schools>
<schoolItem>
<schoolname><i>Best in America®</i>, ASU</schoolname>
<schoolyear>2016</schoolyear>
</schoolItem>
</schools>
</bio>
</StudentItem>
</row>
<row>
<foldername>susan.wissink</foldername>
<status>1</status>
<vhrid>50330</vhrid>
<firstname>Susan</firstname>
<middleinitial>M.</middleinitial>
<lastname>Wissink</lastname>
<title>Student leader</title>
<email>swissink@blank.com</email>
<Office>Phoenix</Office>
<StudentItem>
<practices>
<practice>
<id>681</id>
<name>Real Estate Finance and Lending</name>
</practice>
</practices>
<bio>
<schools>
<schoolItem>
<schoolname><i>Best in America®</i>, UOP</schoolname>
<schoolyear>2011-2015</schoolyear>
</schoolItem>
</schools>
</bio>
</StudentItem>
</row>`
但我正努力让所有的练习和学校成为那个人的一个入口。或多或少我试图让它看起来像下面。
`<StudentItems>
<row>
<foldername>susan.wissink</foldername>
<status>1</status>
<vhrid>50330</vhrid>
<firstname>Susan</firstname>
<middleinitial>M.</middleinitial>
<lastname>Wissink</lastname>
<title>Student leader</title>
<email>swissink@blank.com</email>
<Office>Phoenix</Office>
<StudentItem>
<practices>
<practice>
<id>681</id>
<name>Real Estate Finance and Lending</name>
<id>683</id>
<name>Business and Finance</name>
</practice>
</practices>
<bio>
<schools>
<schoolItem>
<schoolname><i>Best in America®</i>, UOP</schoolname>
<schoolyear>2011-2015</schoolyear>
<schoolname><i>Best in America®</i>, ASU</schoolname>
<schoolyear>2016</schoolyear>
</schoolItem>
</schools>
</bio>
</StudentItem>
</row>`
欢迎任何帮助。谢谢。
答案 0 :(得分:0)
没有样本数据,很难编写代码并进行测试。但通常您需要做的是创建子查询以创建namespace NeilLibrary
{
[InterfaceType(ComInterfaceType.InterfaceIsIDispatch)]
public interface INeilTest
{
[DispId(1)]
string DoMethodReturn(string name);
[DispId(2)]
string DoMethodOut(string name, out string name2, out bool isPrev);
}
[Guid("BA7CC0F2-9C07-4EF9-B799-18D317B7E293")]
[ComVisible(true)]
[ClassInterface(ClassInterfaceType.None)]
[ProgId("NeilLibrary.NeilTest")]
public class NeilTest : INeilTest
{
[ComVisible(true)]
public string DoMethodReturn(string name)
{
return "name: " + name;
}
[ComVisible(true)]
public string DoMethodOut(string name, out string name2, out bool isPrev)
{
name2 = "New Value";
isPrev = true;
return "Name: " + name;
}
}
}
和practice
XML节点。像这样:
schoolItem