Android 5.0+ getRunningTasks已弃用

时间:2015-11-25 14:03:48

标签: android android-5.0-lollipop deprecated android-6.0-marshmallow

我已完成此question和此question。但是在library的帮助下,我现在可以使用以下代码获取前台任务列表。

if (Build.VERSION.SDK_INT < Build.VERSION_CODES.LOLLIPOP) { //For versions less than lollipop
            ActivityManager am = ((ActivityManager) getSystemService(ACTIVITY_SERVICE));
            List<ActivityManager.RunningTaskInfo> taskInfo = am.getRunningTasks(5);
            top = taskInfo.get(0).topActivity.getPackageName();
            Log.v(TAG, "top app = " + top);
        }else{ //For versions Lollipop and above
            List<AndroidAppProcess> processes = ProcessManager.getRunningForegroundApps(getApplicationContext());
            Collections.sort(processes, new ProcessManager.ProcessComparator());
            for (AndroidAppProcess process : processes) {
                if (process.foreground) {
                    top =process.name;
                    Log.v(TAG,top);
                }
            }
        }

在这里,对于Android 5.0+,我得到所有正在运行的前台进程,但我无法断定哪个应用程序是顶级应用程序。

上述代码的输出(for else condition)

com.android.vending
com.google.android.gms
com.google.android.googlequicksearchbox
com.google.android.videos
com.test1
com.naag.testing
com.example.android.gettask

此处我的热门应用是com.google.android.videos

现在如何以编程方式决定com.google.android.videos是上面列表中的顶级应用?

applocker(或类似于applocker)应用程序如何在5.0+上运行? 希望有人帮助对某人有所帮助。

2 个答案:

答案 0 :(得分:3)

所以这是一个更新。在5.0和5.1.1设备中测试。工作得很好。

if (Build.VERSION.SDK_INT < Build.VERSION_CODES.LOLLIPOP) { //For versions less than lollipop
            ActivityManager am = ((ActivityManager) getSystemService(ACTIVITY_SERVICE));
            List<ActivityManager.RunningTaskInfo> taskInfo = am.getRunningTasks(5);
            top = taskInfo.get(0).topActivity.getPackageName();
            Log.v(TAG, "top app = " + top);
        }else{ //For versions Lollipop and above
            List<AndroidAppProcess> processes = ProcessManager.getRunningForegroundApps(getApplicationContext());
            Collections.sort(processes, new ProcessManager.ProcessComparator());
            for (int i = 0; i <=processes.size()-1 ; i++) {
                if(processes.get(i).name.equalsIgnoreCase("com.google.android.gms")) { //always the package name above/below this package is the top app
                    if ((i+1)<=processes.size()-1) { //If processes.get(i+1) available, then that app is the top app
                        top = processes.get(i + 1).name;
                    } else if (i!=0) { //If the last package name is "com.google.android.gms" then the package name above this is the top app
                        top = processes.get(i - 1).name;
                    } else{
                        if (i == processes.size()-1) { //If only one package name available
                            top = processes.get(i).name;
                        }
                    }
                    Log.v(TAG, "top app = " + top);
                }
            }
        }

感谢library

现在我可以在Android 5.0 +中获得前台任务

答案 1 :(得分:0)

“具有使用权限的应用”功能有时可以满足您的需求