我试图使用此查询来获取电影。
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>
SELECT ?movie ?movieTitle ?directorName ?DistributorName ?ArtistName ?Country (CONCAT(STR(MONTH(?ReleaseDate)),
"/",
STR(DAY(?ReleaseDate)),
"/",
STR(YEAR(?ReleaseDate))) as ?displayDate)
WHERE{
?movie rdf:type <http://dbpedia.org/ontology/Film> .
?movie foaf:name ?movieTitle .
?movie dbpedia2:director ?directorName .
?movie dbpedia2:distributor ?DistributorName .
?movie dbpedia2:starring ?ArtistName .
?movie dbpedia2:country ?Country .
?movie <http://dbpedia.org/ontology/releaseDate> ?ReleaseDate .
FILTER(!isLiteral(?movieTitle) || langMatches(lang(?movieTitle), "EN"))
FILTER ((?ReleaseDate >= "2001-01-01"^^xsd:date) && (?ReleaseDate < "2016-01-01"^^xsd:date))
}
ORDER BY DESC(?ReleaseDate)
LIMIT 500 OFFSET 0
但是,结果如下:
movieA - directorA - distributorA - ArtistA - Indonesia - 2012/06/10
movieA - directorA - distributorA - ArtistB - Indonesia - 2012/06/10
movieA - directorA - distributorA - ArtistC - Indonesia - 2012/06/10
movieB - directorD - distributorA - ArtistA - Malaysia - 2013/06/10
movieC - directorA - distributorS - ArtistD - France - 2013/03/10
我希望以这种格式获取数据:
movieA - directorA - distributorA - ArtistA,ArtistB,ArtistC - Indonesia - 2012/06/10
movieB - directorD - distributorA - ArtistA - Malaysia - 2013/06/10
movieC - directorA - distributorS - ArtistD - France - 2013/03/10
答案 0 :(得分:1)
您可以使用GroupConcat执行此操作。因此,您可以修改查询以包含(GROUP_CONCAT(?ArtistName; separator =“,”)作为?艺术家)。当我运行查询时,我注意到导演(列出多个导演的电影)等也会发生同样的事情。所以如果你想把每部电影都放在一行,你可能也需要将它们分组。
示例查询。
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>
SELECT ?movie ?movieTitle ?directorName ?DistributorName(GROUP_CONCAT(?ArtistName ; separator=",") as ?artists) ?Country (CONCAT(STR(MONTH(?ReleaseDate)),
"/",
STR(DAY(?ReleaseDate)),
"/",
STR(YEAR(?ReleaseDate))) as ?displayDate)
WHERE{
?movie rdf:type <http://dbpedia.org/ontology/Film> .
?movie foaf:name ?movieTitle .
?movie dbp:director ?directorName .
?movie dbp:distributor ?DistributorName .
?movie dbp:starring ?ArtistName .
?movie dbp:country ?Country .
?movie <http://dbpedia.org/ontology/releaseDate> ?ReleaseDate .
FILTER(!isLiteral(?movieTitle) || langMatches(lang(?movieTitle), "EN"))
FILTER ((?ReleaseDate >= "2001-01-01"^^xsd:date) && (?ReleaseDate < "2016-01-01"^^xsd:date))
}
ORDER BY DESC(?ReleaseDate)
LIMIT 500 OFFSET 0