Question

我有以下OpenJPA查询（通过db2数据库）：

Select number from Number number where number.uuid = :uuid

列uuid定义为VARCHAR FOR BIT DATA（16）。在实体中，它表示为byte []类型字段。

问题在于，当我第一次使用该查询调用方法时（在WebSphere服务器启动之后），它可以正常工作。相应的调用会导致错误（我甚至启用跟踪日志查看错误的位置）

1st time:> query is running, everything's ok
[11/25/15 13:27:03:803 IST] 0000001d Query         3   openjpa.Query: Trace: Executing query: [Select n from Number n where n.uuid = :uuid] with parameters: ?
[11/25/15 13:27:04:199 IST] 0000001d jdbc_SQL      3   openjpa.jdbc.SQL: Trace: <t 507109353, conn 1755254015> executing prepstmnt -1123134307 SELECT t0.NUMBER_ID, t0.comment, t0.EMPLOYEE_ID, t0.number, t0.RANGE_ID, t0.status, t0.uuid FROM PHONES.Number t0 WHERE (t0.uuid = ?)  [params=?]
[11/25/15 13:27:04:249 IST] 0000001d jdbc_SQL      3   openjpa.jdbc.SQL: Trace: <t 507109353, conn 1755254015> [50 ms] spent
[11/25/15 13:27:04:251 IST] 0000001d jdbc_JDBC     3   openjpa.jdbc.JDBC: Trace: <t 507109353, conn 1755254015> [0 ms] close
2nd time:>
[11/25/15 13:27:09:068 IST] 0000001d Query         3   openjpa.Query: Trace: Executing query: [Select n from Number n where n.uuid = :uuid] with parameters: ?
[11/25/15 13:27:09:556 IST] 0000001d BusinessExcep E   CNTR0020E: EJB threw an unexpected (non-declared) exception during invocation of method "approve" on bean "BeanId(PhoneAllocationEAR#PhoneAllocationEJB.jar#RangeProvider, null)". Exception data: <openjpa-2.1.2-SNAPSHOT-r422266:1548248 nonfatal user error> org.apache.openjpa.persistence.ArgumentException: Failed to execute query "Select n from Number n where n.uuid = :uuid". Check the query syntax for correctness. See nested exception for details.

这是嵌套异常：

Caused by: java.lang.NullPointerException
at org.apache.openjpa.jdbc.sql.DB2Dictionary.setBytes(DB2Dictionary.java:1037)
at org.apache.openjpa.jdbc.sql.DBDictionary.setUnknown(DBDictionary.java:1481)
at org.apache.openjpa.jdbc.sql.DBDictionary.setUnknown(DBDictionary.java:1429)
at org.apache.openjpa.jdbc.kernel.PreparedSQLStoreQuery$PreparedSQLExecutor.executeQuery(PreparedSQLStoreQuery.java:114)
at org.apache.openjpa.kernel.QueryImpl.execute(QueryImpl.java:1005)
at org.apache.openjpa.kernel.QueryImpl.execute(QueryImpl.java:863)
... 86 more

这是一个异常的代码：

public String findByUUID(UUID uuid) {

    TypedQuery<Number> query = em.createQuery("Select n from Number n where n.uuid = :uuid", Number.class);
    ByteBuffer bb = ByteBuffer.allocate(16);
    bb.putLong(uuid.getMostSignificantBits());
    bb.putLong(uuid.getLeastSignificantBits());
    byte[] parameter = bb.array();

    query.setParameter("uuid", parameter);

    List<Number> result = new ArrayList<Number>(query.getResultList());
    return result;
}

*其他信息：如果我从列描述中删除BIT DATA - 我收到另一个错误：

nested exception is: javax.ejb.EJBException: See nested exception; nested exception is: org.apache.openjpa.persistence.PersistenceException: The value of input variable, expression or parameter number "1" cannot be used because of its data type.. SQLCODE=-301, SQLSTATE=07006, DRIVER=4.14.113 {prepstmnt 2039708348 SELECT t0.NUMBER_ID, t0.comment, t0.EMPLOYEE_ID, t0.number, t0.RANGE_ID, t0.status, t0.uuid FROM PHONES.Number t0 WHERE (t0.uuid = ?) [params=?]} [code=-301, state=07006]SQLCA OUTPUT[Errp=SQLRI4A4, Errd=-2145779603, 0, 0, 0, -3700, 0] The value of input variable, expression or parameter number "1" cannot be used because of its data type.. SQLCODE=-301, SQLSTATE=07006, DRIVER=4.14.113 FailedObject: Select n from Number n where n.uuid = :uuid [java.lang.String]

我是通过查看openJPA的来源了解到的，但它同时对我没有帮助。

Answer 1

尝试禁用准备好的查询缓存。众所周知，这是非常错误的。如果需要，您可以搜索OpenJPA JIRA以查找详细信息。

<property name="openjpa.jdbc.QuerySQLCache" value="true(EnableStatistics=true)">

OpenJPA查询第二次失败（可能是因为字节数组参数）

1 个答案: