Question

我只是想知道如何比较字典中的两个对象：

a = {}
while z:
    if a[z] == a[s]:
        print("Correct!")
    else:
        print("You don't know that country.")
    z = input("Enter a country: ")
    s = input("What is the capital of " + z + " ? ")

我想在Correct时打印z = s;当z不在a时，请打印You don't know that country.

Answer 1

假设a是一个以国家/地区为键，字母为值的字典，您应该进行两项单独的检查：首先，您要确保输入的国家/地区作为密钥存在于字典。为此，您应该使用in运算符。其次，您要检查输入的大写是否与字典中的大写相匹配。为此，您使用字典上的国家/地区执行索引访问，并检查该值是否等于输入的资本：

capitals = {
    'Austria': 'Vienna',
    'Belgium': 'Brussels',
    'Denmark': 'Copenhagen',
    'France': 'Paris',
    'Germany': 'Berlin',
    'Netherlands': 'Amsterdam',
    'Norway': 'Oslo',
    'Sweden': 'Stockholm',
    'Switzerland': 'Bern',
    'United Kingdom': 'London'
}

while True:
    country = input("Enter a country: ")

    # abort the loop if the user didn’t enter anything
    if not country:
        break

    # check whether we know that country
    if country in capitals:
        capital = input("What is the capital of {}? ".format(country))

        if capital == capitals[country]:
            print('That was correct!')
        else:
            print('You made a mistake there.')

    else:
        print('I do not know that country, sorry.')

Answer 2

我认为您正在寻找的代码如下。如果没有，请说明您的问题。

dict = {"Germany":"Berlin", "France":"Paris", "Italy":"Rome"}
while 1:
   country = input("Country: ")
   capital = input("Capital: ")
   if(dict[country] == capital):
       print("Correct!")
   else:
       print("Wrong!")

输入必须在行情中。

如何比较字典中的两个对象

2 个答案: