我有两张桌子。有一个表地方,其中包含如下所示的数据:
id name
-----------
1 A1
2 A2
3 A3
4 B1
其他表 place_conditions 包含如下所示的数据:
id placeID desription
----------------------------
1 1 Windy
2 1 Dry
3 3 Wet
4 3 Rainy
4 4 Dry
我喜欢在laravel 4中进行查询,结果如下:
Array
(
[0] => stdClass Object
(
[id] => 1
[name] => A1
[place_cond] => Array
(
[0] => stdClass Object
(
[description] => Windy
)
[1] => stdClass Object
(
[description] => Dry
)
)
)
[1] => stdClass Object
(
[id] => 2
[name] => A2
[place_cond] => Array
(
)
)
[3] => stdClass Object
(
[id] => 3
[name] => A3
[place_cond] => Array
(
[0] => stdClass Object
(
[description] => Wet
)
[1] => stdClass Object
(
[description] => Rainy
)
)
)
)
这是我的部分查询(仍然是错误):
$query = DB::table('place');
if(Input::has('search')){
$query->where(function($a){
$a->where('name','LIKE','%'.Input::get('search').'%');
});
}
/* $query->select('place.*',DB::raw('SELECT Description as place_cond FROM place_conditions WHERE place_conditions.placeID = place.id')); // sub query . Arrggghhhhhh... whyyyy.. stillllll.. errorrrrrrr.. */
$data = $query->get();
是否可以在laravel 4中产生如上所述的结果?你能帮助我吗?谢谢