Question

如果只有一个文件上传控件，我可以传递文件，但是当我使用多个文件上传控件时，我会得到null。

这是我的观点： -

<%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage" %>

<asp:Content ID="indexTitle" ContentPlaceHolderID="TitleContent" runat="server">
    Home Page - My ASP.NET MVC Application
</asp:Content>

<asp:Content ID="indexFeatured" ContentPlaceHolderID="FeaturedContent" runat="server">

</asp:Content>

<asp:Content ID="indexContent" ContentPlaceHolderID="MainContent" runat="server">
    <% using (Html.BeginForm("Index", "Home", FormMethod.Post, new { enctype = "multipart/form-data" })) { %>

   <input name="name" type="text" />
    <input type="file" name="files1" value="" multiple="multiple"/>

     <input type="file" name="files2" value="" multiple="multiple"/>
    <input type="submit" value="Upload You Image"  title="Uplad"/>
    <% } %>
</asp:Content>

这是控制器动作： -

[HttpPost]
        public JsonResult Index(HttpPostedFileBase[] files)
        {
            JsonResult result = new JsonResult();

            foreach (HttpPostedFileBase file in files)
            {
                /*Geting the file name*/
                string filename = System.IO.Path.GetFileName(file.FileName);
                /*Saving the file in server folder*/
                file.SaveAs(Server.MapPath("~/Images/" + filename));
                string filepathtosave = "Images/" + filename;
                /*HERE WILL BE YOUR CODE TO SAVE THE FILE DETAIL IN DATA BASE*/
            }

            return result;
        }

Answer 1

asp.net mvc modelbinding考虑了输入字段的名称。 action方法的参数与任何输入文件字段都不匹配。您需要修改它们，如

[HttpPost]
        public JsonResult Index(HttpPostedFileBase[] files1, HttpPostedFileBase[] files2)
        {
            JsonResult result = new JsonResult();

            foreach (HttpPostedFileBase file in files1)
            {
                /*Geting the file name*/
                string filename = System.IO.Path.GetFileName(file.FileName);
                /*Saving the file in server folder*/
                file.SaveAs(Server.MapPath("~/Images/" + filename));
                string filepathtosave = "Images/" + filename;
                /*HERE WILL BE YOUR CODE TO SAVE THE FILE DETAIL IN DATA BASE*/
            }

            return result;
        }

或者，如果您想要接收相同参数中的所有文件，您可以输入

 <input type="file" name="files[0]" value="" multiple="multiple"/>

     <input type="file" name="files[1]" value="" multiple="multiple"/>

这样，您就不需要更改操作方法的实现

Answer 2

您可以做的最简单的事情是迭代Request.Files：

[HttpPost]
public JsonResult Index()
{
    JsonResult result = new JsonResult();

    foreach (HttpPostedFileBase file in Request.Files)
    {
        ...
    }

    return result;
}

如何在MVC4 C中将多个上传的文件从视图传递到控制器＃

2 个答案: