while循环if语句NULL问题

Question

我似乎无法理解这一点。我究竟做错了什么？我的数据库中有一个表，并且某些行有一个空列，用于＆＃34;公司＆＃34;字段。

我试图在下面的html表中获取＆＃34;用户自己上传的文件。它属于＆＃34; 1629＆＃34;

<?php
// Make a MySQL Connection
mysql_connect("localhost", "", "") or die(mysql_error());
//echo "Connected to MySQL<br />";
mysql_select_db("") or die(mysql_error());
//echo "Connected to Database";

$query = "SELECT company, dmy, COUNT(company) FROM AdTracking WHERE DATE(dmy) = CURRENT_DATE GROUP BY company";

$result = mysql_query($query) or die(mysql_error());

echo "<div style='margin-top:100px;'><center><h2>";
echo date('l jS \ F Y');
echo "<br />";
echo "</h2><center></div>";


echo '
<center> <table class="pure-table pure-table-horizontal">
    <thead>
        <tr>
            <th>Company</th>
            <th>Total</th>
        </tr>
    </thead>
<tbody>
';

// Print out result
while($row = mysql_fetch_array($result)){

    if ($row['company'] == NULL) {
        echo "Users own uploaded files";
    };

    echo "<tr>";
    echo "<td><strong>" . $row['company'] . "</strong></td>";
    echo "<td>" . $row['COUNT(company)'] . "</td>";
    echo "</tr>";
}


echo '
    </tbody>
</table> </center>
';



?>

Answer 1

您正在td和tr之外打印。

您已保持格式。

试试这个

echo "<tr>";
echo "<td><strong>" .($row['company'] == NULL ? "Users own uploaded files" : $row['company']). "</strong></td>";
echo "<td>" . $row['COUNT(company)'] . "</td>";
echo "</tr>";

Answer 2

您应该使用mysql_fetch_assoc()代替mysql_fetch_array()

Answer 3

\n

  

使用mysqli或PDO而不是mysql因为＆＃34; mysql＆＃34;被删除了。