我想将json文档转换为json模式。我用谷歌搜索了它,但没有根据我的要求得到确切的想法。
这里是JSON
{
"empId":1001,
"firstName":"jonh",
"lastName":"Springer",
"title": "Engineer",
"address": {
"city": "Mumbai",
"street": "FadkeStreet",
"zipCode":"420125",
"privatePhoneNo":{
"privateMobile": "2564875421",
"privateLandLine":"251201546"
}
},
"salary": 150000,
"department":{
"departmentId": 10521,
"departmentName": "IT",
"companyPhoneNo":{
"cMobile": "8655340546",
"cLandLine": "10251215465"
},
"location":{
"name": "mulund",
"locationId": 14500
}
}
}
我想生成这样的
{
"$schema": "http://json-schema.org/draft-04/schema#",
"type": "object",
"title": "Employee",
"properties": {
"empId": {
"type": "integer"
},
"firstName":{
"type":"string"
},
"lastName": {
"type": "string"
},
"title": {
"type": "string"
},
"address": {
"type": "object",
"properties": {
"city": {
"type": "string"
},
"street": {
"type": "string"
},
"zipCode": {
"type": "string"
},
"privatePhoneNo": {
"type": "object",
"properties": {
"privateMobile": {
"type": "string"
},
"privateLandLine": {
"type": "string"
}
}
}
}
},
"salary": {
"type": "number"
},
"department": {
"type": "object",
"properties": {
"departmentId": {
"type": "integer"
},
"departmentName": {
"type": "string"
},
"companyPhoneNo": {
"type": "object",
"properties": {
"cMobile": {
"type": "string"
},
"cLandLine": {
"type": "string"
}
}
},
"location": {
"type": "object",
"properties": {
"name": {
"type": "string"
},
"locationId": {
"type": "integer"
}
}
}
}
}
}
}
是否有任何图书馆正在这样做或者是另一种方式?
答案 0 :(得分:1)
答案 1 :(得分:0)
问这个问题已经有一段时间了,但我遇到了同样的问题。到目前为止,我遇到的最好的解决方案是这个库: https://github.com/saasquatch/json-schema-inferrer
我是从 json-schema 文档中找到的。它也有其他语言实现的链接: https://json-schema.org/implementations.html#from-data