使用python 2.4和内置的ZipFile
库,我无法读取非常大的zip文件(大于1或2 GB),因为它希望将未压缩文件的全部内容存储在内存中。有没有其他方法可以做到这一点(使用第三方库或其他一些黑客),或者我必须“解决”并以这种方式解压缩(显然不是跨平台)。
答案 0 :(得分:17)
以下是大文件解压缩的概述。
import zipfile
import zlib
import os
src = open( doc, "rb" )
zf = zipfile.ZipFile( src )
for m in zf.infolist():
# Examine the header
print m.filename, m.header_offset, m.compress_size, repr(m.extra), repr(m.comment)
src.seek( m.header_offset )
src.read( 30 ) # Good to use struct to unpack this.
nm= src.read( len(m.filename) )
if len(m.extra) > 0: ex= src.read( len(m.extra) )
if len(m.comment) > 0: cm= src.read( len(m.comment) )
# Build a decompression object
decomp= zlib.decompressobj(-15)
# This can be done with a loop reading blocks
out= open( m.filename, "wb" )
result= decomp.decompress( src.read( m.compress_size ) )
out.write( result )
result = decomp.flush()
out.write( result )
# end of the loop
out.close()
zf.close()
src.close()
答案 1 :(得分:11)
从Python 2.6开始,您可以使用ZipFile.open()
打开文件上的文件句柄,并将内容有效地复制到您选择的目标文件中:
import errno
import os
import shutil
import zipfile
TARGETDIR = '/foo/bar/baz'
with open(doc, "rb") as zipsrc:
zfile = zipfile.ZipFile(zipsrc)
for member in zfile.infolist():
target_path = os.path.join(TARGETDIR, member.filename)
if target_path.endswith('/'): # folder entry, create
try:
os.makedirs(target_path)
except (OSError, IOError) as err:
# Windows may complain if the folders already exist
if err.errno != errno.EEXIST:
raise
continue
with open(target_path, 'wb') as outfile, zfile.open(member) as infile:
shutil.copyfileobj(infile, outfile)
这使用shutil.copyfileobj()
有效地从打开的zipfile对象读取数据,将其复制到输出文件。