我有以下测试:
public class MyTest extends CamelSpringTestSupport {
@Override
protected AbstractXmlApplicationContext createApplicationContext() {
return new ClassPathXmlApplicationContext(new String[] {
"classpath:my-config.xml",
});
}
@Test
public void testSomething() throws Exception {
Exchange exchange = new DefaultExchange(context);
exchange.getIn().setHeader("myId", "1234");
MessageContentsList parameters = new MessageContentsList();
parameters.add(0, "");
parameters.add(1, "1234");
exchange.getIn().setBody(parameters);
System.out.println("exchange before = " + System.identityHashCode(exchange)); //1657040467
template.send("direct:myRoute", exchange);
Object object = exchange.getOut().getBody();
System.out.println("result = " + object); //null
System.out.println("exchange after = " + System.identityHashCode(exchange)); //1657040467
assertFalse(exchange.isFailed());
}
}
这是路线内的最后一步"直接:myRoute":
public void doSomething(Exchange exchange)
{
System.out.println("exchange within = " + System.identityHashCode(exchange)); //1649140180
exchange.getOut().setBody(1);
}
我的路由由RouteBuilder
类定义,我按
<camelContext id="mainContext" xmlns="http://camel.apache.org/schema/spring">
<packageScan>
<package>com.my.route</package>
</packageScan>
</camelContext>
并且还通过代码动态生成:
((CamelContext) applicationContext.getBean("mainContext")).addRoutes(routeBuilder);
正如您所看到的,当我从测试中调用路由时,我无法检索路由的输出,因为在测试中由于某种原因它是一个不同的交换对象(但是,原始的交换头和属性以某种方式被复制到路线内的交换)。 当我通过XML定义路由时,不会发生此问题。
为什么这样,当我从测试中调用它时,如何检索路由的结果?
答案 0 :(得分:2)
我不是百分百肯定,但我认为你不能这样写。
template.send("direct:myRoute", exchange);
Object object = exchange.getOut().getBody();
理想情况应该是:
Exchange out=null;
out=template.requestBody("direct:myRoute", exchange);
String body=out.getOut().getBody();
为此,您需要将交换模式设置为InOut。 有关模板的更多信息: https://camel.apache.org/maven/current/camel-core/apidocs/org/apache/camel/ProducerTemplate.html