Question

当我尝试执行以下代码时，我收到错误＆＃34;将值添加到＆＃39; smalldatetime＆＃39;列导致溢出＆＃34;：

DECLARE @t TABLE (ID UNIQUEIDENTIFIER, BegDate SMALLDATETIME, EndDate SMALLDATETIME)

INSERT INTO @t
SELECT NEWID(), '19000101', '20151124'

-- This is to show you that nothing is really selected
SELECT 'You will never see it'
FROM @t r1
INNER JOIN @t r2 ON r2.ID = r1.ID
WHERE   1=1
    AND r1.BegDate > r2.BegDate    
    AND r1.EndDate <= r2.EndDate

SELECT r1.ID, r2.BegDate, DATEADD(DAY, -1, r1.BegDate) AS EndDate
FROM @t r1
INNER JOIN @t r2 ON r2.ID = r1.ID
WHERE   1=1
    AND r1.BegDate > r2.BegDate  -- This guarantees that r1.BegDate is not minimal value
    AND r1.EndDate <= r2.EndDate

如您所见，DATEADD（）的结果不能小于最小值。而且，不能调用DATEADD（），因为SELECT必须不返回任何内容。它是SQL服务器的错误吗？

Answer 1

smalldatetime值具有以下日期范围：

1900-01-01至2079-06-06

1900年1月1日至2079年6月6日

您收到错误是因为您的计算导致日期超出此界限：

DECLARE  @BegDate SMALLDATETIME = '19000101'
SELECT @BegDate
SELECT DATEADD(DAY, -1, @BegDate)

问题是SELECT内容在FROM，JOIN和WHERE之前执行的原因，因为这不是Logical Processing Order of the SELECT statement。

如果将19000101值更改为19000102，只是为了获得SQL引擎正在构建的执行计划，您应该看到：

Compute Scalar实际上是DATEADD函数执行：

因此，执行DATEADD函数并抛出错误。这是因为：

请注意，确定语句的实际物理执行由查询处理器和订单可能会有所不同。

SELECT r1.ID, r2.BegDate, IIF(r1.BegDate = '19000101', NULL, DATEADD(DAY, -1, r1.BegDate)) AS EndDate
FROM @t r1
INNER JOIN @t r2 ON r2.ID = r1.ID
WHERE   1=1
    AND r1.BegDate > r2.BegDate  -- This guarantees that r1.BegDate is not minimal value
    AND r1.EndDate <= r2.EndDate

您可以使用OPTION(FORCE ORDER)更改执行计划并使查询正常工作：

SELECT r1.ID, r2.BegDate, DATEADD(DAY, -1, r1.BegDate) AS EndDate
FROM @t r1 
INNER JOIN @t r2 ON r2.ID = r1.ID
WHERE   1=1
    AND r1.BegDate > r2.BegDate  -- This guarantees that r1.BegDate is not minimal value
    AND r1.EndDate <= r2.EndDate
OPTION  (FORCE ORDER)

Answer 2

我在这里收到了答案：

https://social.msdn.microsoft.com/Forums/sqlserver/en-US/1a60b3a1-0e18-41aa-b40a-bc64558f6ce2/tsql-error-adding-a-value-to-a-smalldatetime-column-caused-overflow-sql-server-bug?forum=transactsql&prof=required

在这种情况下，我可以使用OPTION（FORCE ORDER）：

SELECT r1.ID, r2.BegDate, DATEADD(DAY, -1, r1.BegDate) AS EndDate
FROM @t r1
INNER JOIN @t r2 ON r2.ID = r1.ID
WHERE   1=1
    AND r1.BegDate > r2.BegDate  -- This guarantees that r1.BegDate is not minimal value
    AND r1.EndDate <= r2.EndDate
OPTION(FORCE ORDER)

T-SQL错误：将值添加到＆＃39; smalldatetime＆＃39;列导致溢出。 SQL服务器错误？

2 个答案: