我试图用我的C ++程序打开并读取用户输入文件。
我的程序有2个功能; Open_Read()和Enter_Filename()。
Enter_Filename要求用户输入输入文件名（从1到4）。
函数Open_Read打开并读取文件的内容并显示它。
当nb = 1（1 <= nb＆lt; = 4）程序正常工作时，但是nb >=2程序无法打开文件（或找不到文件）。
有人可以帮我找到问题吗？
#include <iostream>
#include <fstream>
using Namespace std;
void Enter_Filename(const int& m, int& nb, char name[], double yy[], double xx[]);
void Open_Read(ifstream&, char filename[], char name[], double yy[], double xx[], int &n, double &sd, char set1[]);
double y[256], x[256];
int main()
{
ifstream in;
char filename[7];
char name[7];
char set1[20];
double yy[4];
double xx[4];
int n = 0;
double sd = 0;
int nb;
int m = 4;
Enter_Filename(m, nb, filename, &yy[4], &xx[4]);
for (int i = 1; i <= nb; i++)
{
Open_Read(in, &filename[i], &name[i], &yy[i], &xx[i], n, sd, &set1[i]);
}
cout << "\n";
system("PAUSE");
return 0;
}
这里有函数Enter_Filename：
void Enter_Filename(const int& m, int& nb, char name[], double yy[], double xx[])
{
cout << "Please Enter the number of articles (1 <= nb <= 4)\n"
"Nb =";
cin >> nb;
if (nb <= m)
{
for (int j = 1; j <= nb; j++)
{
cout << j << ".Article (e.g. input.txt, input1.txt...) =";
cin >> &name[j];
cout << "yy(" << j << ") =";
cin >> yy[j];
cout << "xx(" << j << ") =";
cin >> xx[j];
}
}
}
功能Open_Read：
void Open_Read(ifstream&, char filename[], char name[], double yy[], double xx[], int& n, double &sd, char set1[])
{
ifstream inf;
//cout << "Enter the file name to be opened: ";
//cin >> fileName;
inf.open(filename, ios::in);
if (inf.fail())
{
cout << "Opening " << filename << " file for reading\n";
cout << "---------------------------------------\n";
cout << "The " << filename << " file could not be opened!\n";
cout << "Possible errors:\n";
cout << "1. The file does not exist.\n";
cout << "2. The path was not found.\n";
exit(1);
}
else
{
cout << "fileName:" << filename << endl;
inf >> name >> set1;
inf.ignore(numeric_limits<streamsize>::max(), '\n');
inf >> n >> sd;
for (int i = 1; i <= n; i++)
{
inf >> y[i] >> x[i];
printf("%3i: %10.3f %10.3f\n", i, y[i], x[i]);
}
y[0] = *yy;
x[0] = x[0] + *xx;
for (int i = 1; i <= n; i++)
{
y[i] = y[i - 1] + y[i];
x[i] = x[i] + *xx;
}
}
inf.close();
cout << "NAME:" << name << endl;
cout << "SetID:" << set1 << endl;
cout << "N =" << n << endl;
cout << "SubD =" << sd << endl;
if (inf.fail())
{
cout << "\nThe file " << filename << " could not be closed!\n";
exit(1);
}
return;
}
我使用了两个文件：input.txt和input1.txt：
input.txt
INPUT.TXT
1S12-111-433-3245 K
5 12.0000
0.000 12.290
1.840 0.170
1.480 6.190
1.220 17.100
1.040 25.000
input1.txt
INPUT1.TXT
1S12-111-533-3245 P
3 12.0000
.000 11.780
0.150 34.820
1.840 24.810
答案 0 :(得分：0)
这是您的应用程序的工作版本：
#include "stdafx.h"
#include <iostream>
#include <fstream>
#include <iosfwd>
using namespace std;
void Enter_Filename(const int& m, int& nb, char name[], double yy[], double xx[], int j);
void Open_Read(ifstream&, char filename[], char name[], double yy[], double xx[], int &n, double &sd, char set1[]);
double y[256], x[256];
int main()
{
ifstream in;
char filename[4][10];
char name[7];
char set1[20];
double yy[4];
double xx[4];
int n = 0;
double sd = 0;
int nb;
int m = 4;
cout << "Please Enter the number of articles (1 <= nb <= 4)\n"
"Nb =";
cin >> nb;
if (nb <= m)
{
for (int j = 0; j < nb; j++)
{
Enter_Filename(m, nb, filename[j], &yy[4], &xx[4], j);
}
}
for (int i = 0; i < nb; i++)
{
Open_Read(in, filename[i], &name[i], &yy[i], &xx[i], n, sd, &set1[i]);
}
cout << "\n";
system("PAUSE");
return 0;
}
void Enter_Filename(const int& m, int& nb, char name[], double yy[], double xx[], int j)
{
cout << j << ".Article (e.g. input.txt, input1.txt...) =";
cin >> &name[0];
cout << "yy(" << j << ") =";
cin >> yy[j];
cout << "xx(" << j << ") =";
cin >> xx[j];
}
void Open_Read(ifstream&, char filenames[], char name[], double yy[], double xx[], int& n, double &sd, char set1[])
{
ifstream inf;
//cout << "Enter the file name to be opened: ";
//cin >> fileName;
char filename[11];
memcpy(filename, filenames, 11);
filename[10] = '\0';
inf.open(filename, ios::in);
if (inf.fail())
{
cout << "Opening " << filename << " file for reading\n";
cout << "---------------------------------------\n";
cout << "The " << filename << " file could not be opened!\n";
cout << "Possible errors:\n";
cout << "1. The file does not exist.\n";
cout << "2. The path was not found.\n";
exit(1);
}
else
{
cout << "fileName:" << filename << endl;
inf >> name >> set1;
inf.ignore(numeric_limits<streamsize>::max(), '\n');
inf >> n >> sd;
for (int i = 1; i <= n; i++)
{
inf >> y[i] >> x[i];
printf("%3i: %10.3f %10.3f\n", i, y[i], x[i]);
}
y[0] = *yy;
x[0] = x[0] + *xx;
for (int i = 1; i <= n; i++)
{
y[i] = y[i - 1] + y[i];
x[i] = x[i] + *xx;
}
}
inf.close();
cout << "NAME:" << name << endl;
cout << "SetID:" << set1 << endl;
cout << "N =" << n << endl;
cout << "SubD =" << sd << endl;
if (inf.fail())
{
cout << "\nThe file " << filename << " could not be closed!\n";
exit(1);
}
return;
}
我没有控制你的计算结果，我只确保现在打开你的文件