Question

我有一个字典self.ticketDict1，看起来像这样。

2457 : {'origin': u'HW', 
'department': u'Kunde', 
'ticket-closed': True, 
'prio-events': [(datetime.datetime(2015, 4, 27, 16, 53, 55, 64183, tzinfo=<LocalTimezone "UTC+02:00" 2:00:00>), u'Wichtig')], 
'status-events': [(datetime.datetime(2015, 4, 27, 16, 53, 55, 64183, tzinfo=<LocalTimezone "UTC+02:00" 2:00:00>), u'new'), 
(datetime.datetime(2015, 5, 15, 16, 5, 0, 179351, tzinfo=<LocalTimezone "UTC+02:00" 2:00:00>), u'closed'), 
(datetime.datetime(2015, 5, 28, 13, 32, 47, 523975, tzinfo=<LocalTimezone "UTC+02:00" 2:00:00>), u'closed'), 
(datetime.datetime(2015, 6, 9, 16, 8, 16, 726823, tzinfo=<LocalTimezone "UTC+02:00" 2:00:00>), u'closed')]}

2458 : {'origin': u'HW', 
'department': u'Kunde', 
'ticket-closed': True, 
'prio-events': [(datetime.datetime(2015, 4, 27, 16, 53, 55, 77779, tzinfo=<LocalTimezone "UTC+02:00" 2:00:00>), u'Wichtig')], 
'status-events': [(datetime.datetime(2015, 4, 27, 16, 53, 55, 77779, tzinfo=<LocalTimezone "UTC+02:00" 2:00:00>), u'new'), 
(datetime.datetime(2015, 5, 15, 15, 12, 53, 29570, tzinfo=<LocalTimezone "UTC+02:00" 2:00:00>), u'closed')]}

2459 : {'origin': u'HW', 
'department': u'Kunde', 
'ticket-closed': True, 
'prio-events': [(datetime.datetime(2015, 4, 27, 16, 53, 55, 94126, tzinfo=<LocalTimezone "UTC+02:00" 2:00:00>), u'W\xfcnschenswert')], 
'status-events': [(datetime.datetime(2015, 4, 27, 16, 53, 55, 94126, tzinfo=<LocalTimezone "UTC+02:00" 2:00:00>), u'new'), 
(datetime.datetime(2015, 5, 11, 14, 47, 28, 916677, tzinfo=<LocalTimezone "UTC+02:00" 2:00:00>), u'closed')]}

现在我想从每个项目的第一个status-events值打印所有日历周。

我试过这种方式：

for i in self.ticketDict1:
      print i['status-events'][0][0].isocalendar()[1]

但我总是得到这个错误：

File "/media/sf_Projects/Ticketauswertung/Converting.py", line 86, in ConvertData
print i['status-events'][0][0].isocalendar()[1]
TypeError: 'int' object has no attribute '__getitem__'

编辑：如果我以这种方式打印我的字典：

for i in self.ticketDict1:
            print i, ' : ', self.ticketDict1[i]
            print '\n'

我得到了这个结果：

2556  :  {'origin': u'HW', 'department': u'Intern', 'ticket-closed': False, 'prio-events': [(datetime.datetime(2015, 7, 27, 16, 30, 59, 547747, tzinfo=<LocalTimezone "CEST" 2:00:00>), u'Wichtig')], 'status-events': [(datetime.datetime(2015, 7, 27, 16, 30, 59, 547747, tzinfo=<LocalTimezone "CEST" 2:00:00>), u'new')]}


2557  :  {'origin': u'HW', 'department': u'Intern', 'ticket-closed': False, 'prio-events': [(datetime.datetime(2015, 7, 27, 16, 32, 37, 491657, tzinfo=<LocalTimezone "CEST" 2:00:00>), u'Wichtig')], 'status-events': [(datetime.datetime(2015, 7, 27, 16, 32, 37, 491657, tzinfo=<LocalTimezone "CEST" 2:00:00>), u'new')]}


2558  :  {'origin': u'HW', 'department': u'Intern', 'ticket-closed': False, 'prio-events': [(datetime.datetime(2015, 7, 27, 16, 33, 51, 29451, tzinfo=<LocalTimezone "CEST" 2:00:00>), u'Wichtig')], 'status-events': [(datetime.datetime(2015, 7, 27, 16, 33, 51, 29451, tzinfo=<LocalTimezone "CEST" 2:00:00>), u'new')]}

正如您所看到的，我的字典没有任何问题。

Answer 1

以下对我来说很好：

>>> x = {'status-events': [(datetime.datetime(2015, 4, 27, 16, 53, 55, 64183, None), u'new'), 
(datetime.datetime(2015, 5, 15, 16, 5, 0, 179351, None), u'closed'), 
(datetime.datetime(2015, 5, 28, 13, 32, 47, 523975, None), u'closed'), 
(datetime.datetime(2015, 6, 9, 16, 8, 16, 726823, None), u'closed')]}
>>> x['status-events'][0][0].isocalendar()
(2015, 18, 1)
>>> x['status-events'][0][0].isocalendar()[1]
18

这是因为你循环遍历self.TicketDict1，它将为你提供字典中的每个键。你想要的是这个：

for i in self.TicketDict1['statusevents'].values():
    i[0][0].isocalendar()[1]

我不确定2457是什么（我假设冒号丢失了，应该说2457:），所以你可能会想要这样：

for i in self.TicketDict1[2457]['statusevents'].values():
    i[0][0].isocalendar()[1]

您还希望使用dictionary.values（）来获取值，而不是键。例如：

x = {1:'one', 2:'two'}

for i in x.values():
    print i

>>> one
>>> two

，同时：

x = {1:'one', 2:'two'}

for i in x:
    print i

>>> 1
>>> 2

当您循环代码当前的编写方式时，您将获得密钥。该错误可能来自尝试从字典中的一个键中检索项目，例如。 2457['status-events'][0][0].isocalendar()[1]会抛出错误。

注意：

x = {1:'one', 2:'two'}

for i in x:
    print i[1]

>>> Traceback (most recent call last):
  File "python", line 4, in <module>
TypeError: 'int' object has no attribute '__getitem__'

Answer 2

好的，我自己解决了。不过感谢快速提问！

代码：

for i in self.ticketDict1:
        for j,k in self.ticketDict1[i]['status-events']:
            print i, ' : ', j.isocalendar()[1]
            break

结果：

1459  :  5
1977  :  16
1978  :  16
1979  :  16
2498  :  29
3011  :  44
2500  :  29
3013  :  45

Python：如何从字典中打印某些值

2 个答案: