如何在Symfony中格式化JSON输出

Question

我有一个需要以下输出的脚本：

[{
    "id": "288",
    "title": "Titanic",
    "year": "1997",
    "rating": "7.7",
    "genre": "drama, romance",
    "od": "0"
}, {
    "id": "131",
    "title": "The Bourne Identity",
    "year": "2002",
    "rating": "7.9",
    "genre": "action, mystery, thriller",
    "od": "1"
}]

这看起来不像格式化好的json，就像我这样做：

return new JsonResponse(array(
        "id" => 288,
        "title" => "Titanic",
        "year" => "1997",
        ....
    ));

我得到了这个：

{

"id": ​288,
"title": "Titanic",
"year": "1997"
....
}

我使用的插件是this，它甚至还有一个$.getJson功能？！

如何更改输出格式？

Answer 1

它只是错过了它的外部容器。

试试这个：

return new JsonResponse( array( array(
  "id"    => 288,
  "title" => "Titanic",
  "year"  => "1997"
)) );

这应输出为：

[{"id":288,"title":"Titanic","year":"1997"}]

Answer 2

您必须将items数组包含在父数组中：

return new JsonResponse(array(
    array(
        "id" => 288,
        "title" => "Titanic",
        "year" => "1997",
        ....
    ),
    array(
        "id" => 288,
        "title" => "Titanic",
        "year" => "1997",
        ....
    )
));

Answer 3

您必须将数据放在另一个数组中以创建项目数组。只需将现有数组包装在另一个数组中：

return new JsonResponse(array(
    array(
        "id" => 288,
        "title" => "Titanic",
        "year" => "1997",
        ....
    )
));