Question

我试图使用代码

从日历中获取周数据

public static String[] getpreviousweek(Context context, int num) {

    Log.e("/////////////////", returnPositionIndex(context)+"");
    int year = Integer.parseInt(PrefUtil.getFragYear(context));
    int month = Integer.parseInt(PrefUtil.getFragMonth(context));
    int day = Integer.parseInt(PrefUtil.getFragDay(context));
    Log.e("Year", year + " ");
    Calendar c = new GregorianCalendar(TimeZone.getTimeZone("GMT+05:30"),Locale.UK);
    c.set(year, month, day);
    // Set the calendar to monday of the current week
    c.set(Calendar.DAY_OF_WEEK, Calendar.SUNDAY);
    c.add(Calendar.DATE, num * 7);
    // Print dates of the current week starting on Monday
    SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd", Locale.ENGLISH);
    String[] days = new String[7];
    for (int i = 0; i < 7; i++) {
        days[i] = df.format(c.getTime());
        c.add(Calendar.DAY_OF_MONTH, 1);
    }
    return days;
}

num的值为零..问题是我在摩托罗拉设备中获得了正确的值，并且在nexus中弄错了..无法找到解决方案......

有人请帮我解决一下

Answer 1

使用这些代码行

time==========================================2015-11-24 PM

<强>输出： -

With the following edge weights:
A -> B = 1
B -> A = -2

For c = -1.5, n = 10, 2 solutions are possible:

A -> B -> A -> B -> A
  +1   -2   +1   -2

B -> A -> B -> A -> B
  -2   +1   -2   +1

For c = -100, n = 10, no solution is possible
For c = -1.5, n = 3, no solution is possible


Example of a figure 8-like path, assuming all other edge weights are infinite:

c = -150, n = 10
A -> C -> D -> E -> C -> B -> A
  -99  -99  +1   +1   +1   +1

时区麻烦

1 个答案: