Intent sendIntent = new Intent();
sendIntent.setAction(Intent.ACTION_SEND);
sendIntent.putExtra(Intent.EXTRA_TEXT, "My text");
sendIntent.putExtra(Intent.EXTRA_STREAM, Uri.parse(http://onman.ir/colorfinder/sample.jpg));
sendIntent.setType("*/*");
sendIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
startActivity(Intent.createChooser(sendIntent, "Share using"));
与Gmail
分享意图时,此代码无法附加图片,与共享多个图片或仅限视频的Facebook
共享时也会出错。当我使用sendIntent.setType("image/*")
更改类型时,它会打开Facebook
的共享窗口,但会显示空白文字和图片。
答案 0 :(得分:1)
分享您可以使用此代码
Intent shareIntent = new Intent();
shareIntent.setAction(Intent.ACTION_SEND);
shareIntent.setType("image/*");
shareIntent.putExtra(Intent.EXTRA_TEXT,"abc");
shareIntent.putExtra(Intent.EXTRA_STREAM, imagebitmap);
startActivity(Intent.createChooser(shareIntent, "Share using"));
但是如果你想在Facebook上做,它将不会通过意图你应该使用facebook sdk分享图像和文字
FacebookDialog shareDialog = new FacebookDialog.ShareDialogBuilder(this)
.setLink(url)
.setCaption(getString(R.string.fb_share))
.setDescription(getString(R.string.fb_share))
.setPicture(
"https://scontent-lhr3-1.xx.fbcdn.net/hphotos-xfp1/v/t1.0-9/11899955_1616850925232395_9146772907853639083_n.jpg?oh=3dd7da7bf03edee84689d66af2024880&oe=56793D62")
.build();
uiHelper.trackPendingDialogCall(shareDialog.present());
dismissProgressBar();
并且在您的代码中,您首先需要获取位图,然后共享位图而不是网址
答案 1 :(得分:1)
private void shareImage(){ Intent share = new Intent(Intent.ACTION_SEND);
// If you want to share a png image only, you can do:
// setType("image/png"); OR for jpeg: setType("image/jpeg");
share.setType("image/*");
// Make sure you put example png image named myImage.png in your
// directory
String imagePath = Environment.getExternalStorageDirectory()
+ "/myImage.png";
File imageFileToShare = new File(imagePath);
Uri uri = Uri.fromFile(imageFileToShare);
share.putExtra(Intent.EXTRA_STREAM, uri);
startActivity(Intent.createChooser(share, "Share Image!"));
试试此代码
请注意,当您使用setType()方法时,您将启用Android来过滤哪些应用可以共享您的内容。例如,您正在共享文本或URL,要显示的相应应用程序可以是Facebook,消息或电子邮件。如果您正在分享图片,那么正确的应用可以是Instagram,Snapped或Picasa。
答案 2 :(得分:0)
这个对我有用
Intent shareIntent = new Intent(android.content.Intent.ACTION_SEND);
shareIntent.setType("image/jpeg");
shareIntent.putExtra(android.content.Intent.EXTRA_SUBJECT, getResources().getString(R.string.share_subject));
shareIntent.putExtra(android.content.Intent.EXTRA_TEXT, getResources().getString(R.string.share_message));
shareIntent.putExtra(Intent.EXTRA_STREAM, Uri.parse(yourimagepath);
startActivity(Intent.createChooser(shareIntent, "Share Image"));
答案 3 :(得分:0)
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (requestCode == UPLOADIMAGE && resultCode == RESULT_OK)
{
uploadImage.setVisibility(View.GONE);
imageView.setVisibility(View.VISIBLE);
if (data !=null)
{
imageUri=data.getData();
imageView.setImageURI(imageUri);
Uri selectedImage = data.getData();
String[] filePathColumn = { MediaStore.Images.Media.DATA };
Cursor cursor = getContentResolver().query(selectedImage,filePathColumn, null, null, null);
cursor.moveToFirst();
columnIndex = cursor.getColumnIndex(filePathColumn[0]);
attachmentFile = cursor.getString(columnIndex);
Log.e("Attachment Path:", attachmentFile);
URI = Uri.parse("file://" + attachmentFile);
cursor.close();
}
else {Toast.makeText(TutorForm.this,"Uploading image failed",Toast.LENGTH_LONG).show();}
}
super.onActivityResult(requestCode, resultCode, data);
OnClickListner
Intent emailIntent=new Intent(Intent.ACTION_SENDTO, Uri.parse("mailto:"+ clientEmail));
emailIntent.putExtra(Intent.EXTRA_TEXT,body);
emailIntent.putExtra(Intent.EXTRA_SUBJECT,"Tutor Registration from App");
emailIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
Uri uri = Uri.parse(imageUri.toString());
emailIntent.putExtra(Intent.EXTRA_STREAM,URI);
startActivity(Intent.createChooser(emailIntent,"Send Via..."));
答案 4 :(得分:0)
shareIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
shareIntent.setType("image/*");
//set your message
shareIntent.putExtra(android.content.Intent.EXTRA_TEXT, msgText);
String imagePath = Environment.getExternalStorageDirectory() +
File.separator + "image_name.jpg";
File imageFileToShare = new File(imagePath);
Uri uri = Uri.fromFile(imageFileToShare);
shareIntent.putExtra(Intent.EXTRA_STREAM, uri);
Uri uri = Uri.fromFile(imageFileToShare);
sharingIntent.putExtra(Intent.EXTRA_STREAM, uri);