Question

conn = new SqlConnection("Data Source=127.0.0.1;Initial Catalog=TestLang;Integrated Security=True");
DataSet ds = new DataSet();

SqlDataAdapter adapter = new SqlDataAdapter(
      "SELECT * FROM Employee; SELECT * FROM Tbl_Translate", conn);
            adapter.TableMappings.Add("Table", " ");
            adapter.TableMappings.Add("Table1", " ");

conn.Open();
adapter.Fill(ds);
conn.Close();

ds.DataSetName = "TOURLIST";

ds.WriteXml(@"C:\Te\Xml1.xml");
richTextBox1.Text = File.ReadAllText(@"C:\Te\Xml1.xml");

此代码生成此文件

<?xml version="1.0" standalone="yes"?>
<TOURLIST>
     <ID>1</ID>
     <FirstName> mohammad </FirstName>
     <LastName>neshasteh</LastName>
     <Designation>no</Designation>

     <ID>2</ID>
     <FirstName>ali</FirstName>
     <LastName />
     <Designation>Has</Designation>

     <ID>3</ID>
     <FirstName>ace</FirstName>
     <LastName>eca</LastName>
     <Designation />
</TOURLIST>

但我想导出这种格式

<?xml version="1.0" standalone="yes"?>
<TOURLIST>
     <ID>1</ID>
     <FirstName>mohammad</FirstName>
     <LastName>neshasteh</LastName>
     <Designation>no</Designation>
     <ID>2</ID>
     <FirstName>ali</FirstName>
     <LastName />
     <Designation>Has</Designation>
     <ID>3</ID>
     <FirstName>ace</FirstName>
     <LastName>eca</LastName>
     <Designation />
</TOURLIST>

Answer 1

也许它不是最好的方法，但你可以遍历你的xml并构建字符串。

public static string GetFormat(string xmlString)
{
    var xml = XDocument.Parse(xmlString);
    var builder = new StringBuilder();
    BuildString(xml, builder);

    return builder.ToString();
}

public static void BuildString(XContainer container, StringBuilder builder)
{
    var element = container as XElement;

    if (element != null && !element.HasElements && !string.IsNullOrEmpty(element.Value))
    {
        builder.Append(element.Value + " ");
    }

    foreach (var xElement in container.Elements())
    {
        BuildString(xElement, builder);
    }
}

Answer 2

你的数据集中可能有2个表吗？

所以，而不是：

ds.WriteXml(@"C:\Te\Xml1.xml");

尝试类似：

ds.Tables(0).WriteXml(@"C:\Te\Xml1.xml");

或：

ds.Tables("tableName").WriteXml(@"C:\Te\Xml1.xml");

希望这有帮助！

Answer 3

另一种方法是在sql中生成xml，然后将结果写入xml文件。下面的代码在t-sql中：

SELECT TOP 1 *
FROM dbo.Employee
FOR XML AUTO

我需要用C＃生成这个XML文件，但我不能

3 个答案: