我的型号代码
public function retrivecat()
{
$query = $this->db->get('category');
foreach ($query->result() as $row)
{
$data[] = $row->catname;
}
return $data;
}
我的控制器代码
function addPost()
{
$username = $this->session->userdata('username');
$data = array(
'pageTitle' => 'ارسال مطلب',
'username' => $username
);
$this->load->model('category');
$data = $this->category->retrivecat();
$this->load->view('dashboard/post',$data);
}
我的观看代码:
print_r($data);
exit();
但是,这不起作用并显示:
遇到PHP错误
严重性:注意
消息:未定义的变量:数据
文件名:dashboard / post.php
行号:72
答案 0 :(得分:0)
要将变量传递到视图中,您必须执行以下操作:
function addPost()
{
$username = $this->session->userdata('username');
$data = array(
'pageTitle' => 'ارسال مطلب',
'username' => $username
);
$this->load->model('category');
$data['variable'] = $this->category->retrivecat();
$this->load->view('dashboard/post',$data);
}
然后在视图中执行print_r($variable);