Question

这是我的代码

students=["X" ,"Y" ,"Z" ]
age=[20,22,26]

def names():
    global students
    for students in students: 
        print "your name is"+" "+students+" "+"your age is" 
names()

def ages():
    global age
    for age in age: 
        print age 

ages()

想要输出

your name is X your age is 20  
your name is Y your age is 22 
your name is Z your age is 26

实际输出

your name is X your age is  
your name is Y your age is  
your name is Z your age is  
20 
22 
26

如何逐个执行这些功能并获得所需的输出。

Answer 1

试试这个

char

Answer 2

>>> students=["X" ,"Y" ,"Z" ]
>>> age=[20,22,26]
>>> d = dict(zip(students, age))
>>> for k, v in d.items():
        print 'your name is', k ,'your age is', v

Answer 3

students=["X" ,"Y" ,"Z" ]
age=[20,22,26]

for i, name in enumerate(students):
    print "your name is", name, "and your age is", age[i]

修改

必须承认，使用zip作为另一个答案说更容易理解。

Answer 4

你可以做的是迭代学生并使用枚举保持索引i。

for i, student in enumerate (students):
    print "Your name is " + student +", "+ age[i]

如何在python中逐个执行两个函数并获得所需的输出

4 个答案: