Question

我已经编写了下面的代码，我想返回一个pqpageId，日期和小时，它具有最小计数。提前谢谢。

代码：

WITH CTE AS (
                  SELECT PQIM.PQPageID
                        ,PQIM.PageURL as PageDescription
                        ,CONVERT(Date,NCPI.RequestDateTime) AS [Date]
                        ,DATEPART(HOUR,NCPI.RequestDateTIme) AS [HOUR]
                        ,ISNULL (COUNT(NCPI.PQPageID),0)AS HourlyPQPageIdCount

                    FROM dbo.NewCarPurchaseInquiries AS NCPI WITH (NOLOCK) 
                    RIGHT JOIN  dbo.PQPageIds_MasterTblFrom3rdNov2015 AS PQIM  WITH (NOLOCK)
                                ON PQIM.PQPageID = NCPI.PQPageId
                                --WHERE NCPI.RequestDateTime between dateadd(hour, -1, getdate()) and getdate()   
                                WHERE CONVERT(DATE,NCPI.RequestDateTime) >= '2015-11-04'
                                AND DATEPART(hour,NCPI.RequestDateTime) between 8 and 23
                        GROUP BY PQIM.PQPageId,CONVERT(Date,NCPI.RequestDateTime), DATEPART(HOUR,NCPI.RequestDateTIme),PQIM.PageURL 
                    )

    SELECT  CT.PQPageId , CT.Date ,CT.HOUR, MIN( CT.HourlyPQPageIdCount)AS MINCOUNT          
    FROM CTE CT WITH (NOLOCK)
    GROUP BY  CT.PQPageId , CT.Date ,HourlyPQPageIdCount,CT.HOUR
    ORDER BY MINCOUNT,CT.[HOUR],CT.[Date], PQPageID asc  

Output : 

PQPageId    Date    HOUR    MINCOUNT
1   04-11-2015  8   2359

1   05-11-2015  8   2332

1   06-11-2015  8   2008

1   07-11-2015  8   1964

1   08-11-2015  8   2139

1   09-11-2015  8   54


2   04-11-2015  9   10

2   11-11-2015  9   56

但我期待

PQPageId ||日期||小时|| MINCOUNT

1 09-11-2015 8 54

2 04-11-2015 9 10

Answer 1

您可以尝试以下代码：

WITH CTE AS (...)
SELECT PQPageId, Date, HOUR, HourlyPQPageIdCount AS MINCOUNT
FROM (
   SELECT  PQPageId, Date, HOUR, HourlyPQPageIdCount
           RANK() OVER(PARTITION BY HOUR ORDER BY HourlyPQPageIdCount) AS r
   FROM CTE WITH (NOLOCK) ) A
WHERE r = 1

返回每小时最小列数？

1 个答案: