Question

import random

print("Pick a number from 1-50")

randomNumber = random.randint(1,50)
correct = False

while not correct:
    try:
        userInput = int(input("Insert your number here. "))
    except ValueError:
        print("That is not a Number!")
        continue
    if userInput > randomNumber:
        print("Guess lower.")
    elif userInput < randomNumber:
        print("Guess Higher.")
    else:
        print("You got it!")
        break

因此，此代码当前接受用户输入并说明用户是否猜到了随机整数，或者是否应该猜测更高/更低。我想编辑代码，现在说明用户输入是否在随机整数的5,10,15等之内。

因此，如果随机整数是30，并且用户输入20，那么程序会说＆＃34;你在10以内;猜得更高。＆＃34;

有什么建议吗？我对python非常陌生，所以如果可能的话，请用更简单的方法回复。

感谢。

PS：哦，最好不要使用模块，主要是因为我还在学习。

Answer 1

我认为这可以满足您的需求，并且可以减少if链：

import random

print("Pick a number from 1-50")

randomNumber = random.randint(1,50)
correct = False

while not correct:
    try:
        userInput = int(input("Insert your number here. "))
    except ValueError:
        print("That is not a Number!")
        continue
    if randomNumber == userInput: # Let's check this first!
        print ("YOU WIN!!!")
        break # We use break b/c changing correct would still run rest of loop

    acceptable_ranges = [5, 10, 15, 20, 25, 30, 25, 40, 45, 50]
    guess_error = userInput - randomNumber
    i = 0
    while abs(guess_error) > acceptable_ranges[i]: # see how close they are
        i += 1
    if guess_error < 0: # let's figure out where they need to go
        next_guess_direction = "higher"
    else:
        next_guess_direction = "lower"

    print (("You are within %i: Please guess %s")
           %(acceptable_ranges[i], next_guess_direction))

我们来看看。在最后if语句中稍微进一步，最后print行。我们正在检查上面定义的guess_error（第15行）guess_error = userInput - randomNumber是否小于0（否定）。如果它小于零，那么我们使变量next_guess_direction等于字符串“higher”，因为下一个猜测需要大于最后一个（randomNumber大于{{1}如果userInput不是负数，那么它是正数，因为我们已经消除了我们消除0的可能性：

guess_error

因此，如果guess_error是肯定的，我们知道if randomNumber == userInput: # Let's check this first! print ("YOU WIN!!!")大于userInput，我们将randomNumber设置为等于字符串“lower”。最后，我们打印出我们发现的所有内容：

next_guess_direction

我使用的是较旧版本的格式，其中print (("You are within %i: Please guess %s") %(acceptable_ranges[i], next_guess_direction))和%i分别是整数和字符串的占位符。然后我使用%s定义应该在那里格式化的内容，这只是意味着将%(acceptable_ranges[i], next_guess_direction)放入整数并将acceptable_ranges[i]放入字符串中。请注意，我们在if语句正上方的next_guess_direction中找到i。

我知道这很长，但我不知道你需要多少细节！

Answer 2

更新：我看到你要求在没有模块的情况下这样做。这是一个解决方案：

def ceil(xx):
    if int(xx) < xx:
        return int(xx) + 1
    else:
        return int(xx)

def generate_response(actual, guess, interval=5):
    diff_interval_units = (guess - actual) / float(interval)
    within = ceil(abs(diff_interval_units)) * interval
    response = "You are within %d" % within
    if diff_interval_units > 0:
        response += "; guess lower"
    elif diff_interval_units < 0:
        response += "; guess higher"
    return response

- 原始答案：您可以使用numpy的ceil函数执行此操作。

例如：

import numpy as np

def generate_response(actual, guess, interval=5):
    diff_interval_units = (guess - actual) / np.float(interval)
    within = np.ceil(np.abs(diff_interval_units)) * interval
    response = "You are within %d" % within
    if diff_interval_units > 0:
        response += "; guess lower"
    elif diff_interval_units < 0:
        response += "; guess higher"
    return response

Answer 3

使用modulo operator的解决方案：

import random
randomNumber = random.randint(0,100)

def guess(divisor = 5):
    while 1:
        try:
            print("Pick a number from 0-100")
            userInput = int(input("Insert your number here: "))
        except ValueError:
            print("That is not a Number!")
            continue

        delta = randomNumber - userInput

        if delta == 0:
            print("You got it!")
            return

        remainder = delta % divisor
        # this takes advantage of python truncating non-floating point numbers
        rounded_delta = (abs(delta) / divisor) * divisor + divisor * bool(remainder)

        high_or_low = 'higher' if delta > 0 else 'lower'
        print("You are within %s. Guess %s." % (rounded_delta, high_or_low))

如何让我的程序检查用户输入是否在随机整数的5,10,15,20等之内？

3 个答案: