Question

我的数据库表中有一些数据，当我尝试获取它并使用mysqli_fetch_assoc()显示并在网页上显示我失败时可以请一些人帮我知道我在做错了

我的桌子（沙龙）包括栏目：

saloon_sex

saloon_map

saloon_price

saloon_name

saloon_number

saloon_image

saloon_location

saloon_oh

saloon_oh1

saloon_services

saloon_menu1

saloon_menu2

saloon_menu3

saloon_photo1

saloon_photo2

saloon_photo3

saloon_area

这是代码

<?php 
              $connection = mysqli_connect('localhost','root','') or die(mysqli_error($connection));
                            mysqli_select_db($connection,'cmssite') or die (mysqli_error($connection));
            if($connection){
                              echo('connected to database');
                           }
              if(isset($_POST['submit'])) {
                   if(isset($_POST['area'])) {

                      $search_value = $_POST['area'];
                      $query = mysqli_query( $connection,"select * from saloon where saloon_area LIKE '%$search_value%'");
                if(! $query )
                         {
                               die('Could not get data: ' . mysqli_error($query));
                         }

                   $row=null;
                  // $row=mysqli_fetch_assoc($query);
                while ($row=mysqli_fetch_array($query))
                 {      echo  $row['saloon_name'];}     
                 ?>


            <div class="row">
                <div class="col-md-4">
                    <img src="images/toni&guysalon.jpg" height="150" width="150"/></a>
                </div>

                <div class="col-md-5">
                    <h3 style="font-weight:bold; margin-top:10px;"><?php echo  $row['saloon_name']?></h3>
                    <img src="images/unisex.png" width="15" height="15"> <?php echo $row['saloon_sex']?>
                    <div class="clearfix" style="height:10px;"></div>
                    <img src="images/location.png" width="15" height="15"> Opposite Nerus Emporio, Madhapur
                    <div class="clearfix" style="height:10px;"></div>
                    <img src="images/rupee.png" width="15" height="15"> 400+ For Haircut
                    <div class="clearfix" style="height:10px;"></div>
                    <img src="images/time.png" width="15" height="15"> Mon to Sun - 10:00 AM to 09:30 PM

                </div>
            </div>
                   <?php } }

               ?>
            [p1][1]

p2

Answer 1

<h3 style="font-weight:bold; margin-top:10px;"><?php echo  $row['saloon_name']?></h3>
<img src="images/unisex.png" width="15" height="15"> <?php echo $row['saloon_sex']?>

改变它

<h3 style="font-weight:bold; margin-top:10px;"><?php echo  $row['saloon_name'];?></h3>
<img src="images/unisex.png" width="15" height="15"> <?php echo $row['saloon_sex'];?>

Answer 2

如果您想使用条件mysqli_fetch_assoc或mysqli_fetch_array，您必须将要打印的代码保留在条件的范围内。你做错了，因为你只需要检索，打印并关闭它。

  while ($row=mysqli_fetch_array($query))
             {      echo  $row['saloon_name'];}

这是我在输入时总是会做的。

 while ($row = mysqli_fetch_assoc($query)) {

 <div class="col-md-5">
                <h3 style="font-weight:bold; margin-top:10px;"><?php echo  $row['saloon_name']?></h3>
                <img src="images/unisex.png" width="15" height="15"> <?php echo $row['saloon_sex']?>
                <div class="clearfix" style="height:10px;"></div>
                <img src="images/location.png" width="15" height="15"> Opposite Nerus Emporio, Madhapur
                <div class="clearfix" style="height:10px;"></div>
                <img src="images/rupee.png" width="15" height="15"> 400+ For Haircut
                <div class="clearfix" style="height:10px;"></div>
                <img src="images/time.png" width="15" height="15"> Mon to Sun - 10:00 AM to 09:30 PM
        </div>
               <?php
               } // closing tag for mysqli_fetch_assoc/array
           ?>

您可以通过检索并将其保存到有意义的变量中来执行此操作：

   while($row = mysqli_fetch_assoc($query)) {
 $saloonSex = $row['saloon_sex'];
 $saloonPrice = $row['saloon_price'];
 $saloonName = $row['saloon_name'];
 ... etc etc
 <div class="col-md-5">
     <h3 style="font-weight:bold; margin-top:10px;"><?php echo $saloonName?></h3>
     <img src="images/unisex.png" width="15" height="15"> <?php echo $saloonSex?>
  .....etc etc

  <?php
    } // closing tag for mysqli_fetch_assoc/array
 ?>

希望它能解决你的问题。

无法从数据库中检索数据

2 个答案: