Question

我是Java的新手（C ++和C是我常用的语言）

我试图弄清楚如何对一组对象进行排序。我需要让用户输入有多少玩家，玩家姓名和玩家分数。然后程序将从顶部到底部输出得分和球员名称。

我让用户输入他们的信息，并将其存储到播放器类。

我无法弄清楚如何对玩家对象分数进行排序。我很确定我需要使用类比，但对于我的生活，我无法弄清楚如何设置它。

有人可以帮忙吗？

我知道播放器类中的代码不正确lol

import java.util.*;
import java.util.Arrays;

public class HelloWorld {
    public static void main(String[] args){

        Scanner input = new Scanner(System.in);
        Scanner input1 = new Scanner(System.in);
        int allPlayers;
        int index[] = new int[12];
        int i= 0;
        System.out.print("Please enter the number of players");
        allPlayers = input.nextInt();

        Player[]  playersArray = new Player[allPlayers];

        for(i = 0; i <allPlayers; i++){
            playersArray[i] = new Player();
            System.out.print("What is the name of Player # " + (i+1) +"?");
            playersArray[i].name = input1.nextLine();
          System.out.print("What was the score of Player # " + (i+1) + "?");
            playersArray[i].score = input.nextInt();
        }

              System.out.print(playersArray[i].name);
              System.out.print(playersArray[i].score);
    }
}
public class Player implements Comparable<Player> {
    private int score;    // players score 
    private String name;  // players name

    public Player(int score, String name){
        this.core = score;
        this.name = name;
    }
    public int compareTo(Player other){
        int last = this.score.compareTo(other.score);
        return last == 0 ? this.name.compareTo(other.score) : score;
    }
}

Answer 1

代码中的问题是对compareTo()方法的误解。

如果第一个参数（在本例中，this被认为是第一个参数）更大，则方法返回-1，如果它们相等则返回0，如果第二个参数更大，则返回1。

public int compareTo(Player other){
    if (other == null){
        return -1; // If the other is null, it goes last
    }

    // First, compare by the score:
    int scoreComparison = Integer.compare(this.score, other.score);

    // That's good enough, unless the scores are equal
    if (scoreComparison != 0){ // then they're not equal, so we know our answer
        return scoreComparison;
    } else { // The scores are equal, so compare the names and return the result
        if (this.name == null){ // Equal if both null, otherwise non-null wins
            return other.name == null ? 0 : 1;
        } else {
            return this.name.compareTo(other.name);
        }
    }
}

Answer 2

蛋糕走路。做了一些简化和清理。

class Player implements Comparable<Player> {
    public final int    score;  // players score
    public final String name;   // players name

    public Player(final int score, final String name) {
        this.score = score;
        this.name = name;
    }
    @Override public int compareTo(final Player other) {
        return other.score - this.score;
        // return this.score - other.score; // or this to reverse order
    }
}

public class PlayerSorting {

    public static void main(final String[] args) {
        try (final Scanner input = new Scanner(System.in);//
                final Scanner input1 = new Scanner(System.in);) {
            System.out.print("Please enter the number of players");
            final int allPlayers = input.nextInt();

            final Player[] playersArray = new Player[allPlayers];
            for (int i = 0; i < allPlayers; i++) {
                System.out.print("What is the name of Player # " + (i + 1) + "?");
                final String name = input1.nextLine();
                System.out.print("What was the score of Player # " + (i + 1) + "?");
                final int score = input.nextInt();
                playersArray[i] = new Player(score, name);
            }

            // sort
            Arrays.sort(playersArray);

            // output all
            System.out.println("SCORES:");
            for (final Player player : playersArray) {
                System.out.println("\t" + player.name + "\t" + player.score);
            }
        }
    }

}

尝试对Java对象数组进行排序

2 个答案: