Question

刚开始学习Python / Pygame观看视频和阅读学习。我想看一个示例代码，在鼠标按下的矩形按钮上循环3个图像并返回到第一个图像。我真的希望这些图片有三个选项并返回不同的结果。因此能够在触发执行选择时循环图像能够选择选项和选项。

Answer 1

实施例

import pygame

pygame.init()

screen = pygame.display.set_mode((300,200))

# three images 
images = [
    pygame.Surface((100,100)),    
    pygame.Surface((100,100)),    
    pygame.Surface((100,100)),    
]

images[0].fill((255,0,0))
images[1].fill((0,255,0))
images[2].fill((0,0,255))

# image size and position    
images_rect = images[0].get_rect()

# starting index
index = 0

running = True

while running:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False
        elif event.type == pygame.MOUSEBUTTONDOWN:
            # check mouse position and pressed button
            if event.button == 1 and images_rect.collidepoint(event.pos):
                # cycle index
                index = (index+1) % 3

    screen.blit(images[index], images_rect)
    pygame.display.flip()

pygame.quit()

使用类的示例 - 创建许多按钮

import pygame

class Button(object):

    def __init__(self, position, size):
        self._images = [
            pygame.Surface(size),    
            pygame.Surface(size),    
            pygame.Surface(size),    
        ]

        self._images[0].fill((255,0,0))
        self._images[1].fill((0,255,0))
        self._images[2].fill((0,0,255))

        self._rect = pygame.Rect(position, size)

        self._index = 0

    def draw(self, screen):
        screen.blit(self._images[self._index], self._rect)

    def event_handler(self, event):
        if event.type == pygame.MOUSEBUTTONDOWN:
            if event.button == 1 and self._rect.collidepoint(event.pos):
                self._index = (self._index+1) % 3


pygame.init()

screen = pygame.display.set_mode((320,110))

button1 = Button((5, 5), (100, 100))
button2 = Button((110, 5), (100, 100))
button3 = Button((215, 5), (100, 100))

running = True

while running:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False
        button1.event_handler(event)
        button2.event_handler(event)
        button3.event_handler(event)

    button1.draw(screen)
    button2.draw(screen)
    button3.draw(screen)

    pygame.display.flip()

pygame.quit()

Answer 2

如果我正确理解了这个问题，你需要一个按钮，每次点击它时都会改变外观，并相应地改变它的相对功能。

您应该能够通过创建一个带有两个列表和一个计数器

的类来解决您的问题

1）图像列表

2）功能列表

3）计数器告诉您选择了哪个图像/功能。

需要在类中构建函数，但是您可以在类参数中提供所需的图像（实际上，您可以将它们作为参数传递，但我认为不值得）。

这是代码，我评论了一些具有预期含义的行（在行注释中）

import pygame
import sys
pygame.init()

width = 600
height = 400

screen = pygame.display.set_mode((width, height))
pygame.display.set_caption("Magic Buttons")
background = pygame.Surface(screen.get_size())

clock = pygame.time.Clock()

class Buttons:
    def __init__(self, posX, posY, image1, image2, image3):
        self.image_list = [image1, image2, image3] # static list of images 
        self.function_list = [self.button_function_1,self.button_function_2,self.button_function_3 ]
        self.rect_position = (posX, posY) # this is a tuple to identify the upper left corner of the rectangle of the image
        self.button_type = 0 # initial value of the button, both for the function and the image
        self.image = pygame.image.load(self.image_list[0]) #default image, index number 0 of image_list
        self.rect = pygame.Rect(posX, posY, self.image.get_width(), self.image.get_height()) # create a rectangle object same size of the images

    def check(self, pos):
        if self.rect.collidepoint(pos) ==True:
            self.change_button()
        else:
            pass

    def change_button(self):
        self.button_type = (self.button_type +1)%3
        self.image = pygame.image.load(self.image_list[self.button_type ]) # load the image relative to button_type
        self.function_list[self.button_type -1]() # execute the function relative to the new value of button_type
        self.draw_button()

    def draw_button(self):
        screen.blit(self.image, self.rect_position) # blit the new button image

    def button_function_1(self):
        print ("function 1 in action")

    def button_function_2(self):
        print ("function 2 in action")

    def button_function_3(self):
        print ("function 3 in action")


multibutton = Buttons(100,100,"button1.png","button2.png","button3.png") # create an istance of the button in the x=100, y = 100, with the three image button



while True:
    background.fill((0,0,0))

    clock.tick(30)

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            sys.exit()
        if event.type == pygame.MOUSEBUTTONUP:
            pos = pygame.mouse.get_pos() # fetch the position of the mouse
            multibutton.check(pos) # check if the mouse is on the button

    multibutton.draw_button()

    pygame.display.flip()

如何在矩形按钮上循环3个图像？

2 个答案: