Question

我正在使用此模型设置Devise：

access.rb

class Access < ActiveRecord::Base
  include UUIDHelper

  # Include default devise modules. Others available are:
  # :confirmable, :lockable, :timeoutable and :omniauthable
  devise :database_authenticatable, :registerable, :recoverable, :rememberable, :trackable, :validatable

  belongs_to :verification
  belongs_to :actor, autosave: true

  validates_presence_of :username
  validates :username, uniqueness: true
  validates_length_of :username, maximum: 64
  validates_length_of :username, minimum: 3

  # Returns the hash digest of the given string. Used for SEEDS FILE
  def Access.digest(string)
    cost = ActiveModel::SecurePassword.min_cost ? BCrypt::Engine::MIN_COST :
        BCrypt::Engine.cost
    BCrypt::Password.create(string, cost: cost)
  end
end

20150304041353_create_accesses.rb

class CreateAccesses < ActiveRecord::Migration
  def change
    create_table :accesses, :id => false  do |t|
      t.string :id, limit: 36, primary: true, null: false
      t.string :actor_id, limit: 36, :required => true
      t.string :username, :limit => 64
      t.timestamps
    end
  end
end

这些是来自控制器的命令：

 def processAccess(params)
    @access.username = params[:access][:username]
    @access.password = params[:access][:password]
    @access.email = params[:access][:email]
    @access.actor = @actor
    @access.save!
  end

我正在尝试访问数据库中的注册或“添加”。但是一旦我取消注释'设计'它就行不通。我也试过在rails console中手动输入它;它确实有效..我错过了什么？

Answer 1

您需要在Access的操作中初始化controller模型，如：

@access = Access.new

在将任何值分配给@access实例变量之前。

设计模型无法工作

1 个答案: