我有一种方法,通过将其分解为NSDateComponents,将小时和秒组件从NSDate中提取出来。我的代码如下......
unsigned hourAndMinuteFlags = NSHourCalendarUnit | NSMinuteCalendarUnit;
NSCalendar* calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
[calendar setTimeZone:[NSTimeZone timeZoneWithName:@"GMT"]];
NSDateComponents* travelDateTimeComponents = [calendar components:hourAndMinuteFlags fromDate:travelDate];
NSString* hours = [NSString stringWithFormat:@"%02i", [travelDateTimeComponents hour]];
NSString* minutes = [NSString stringWithFormat:@"%02i", [travelDateTimeComponents minute]];
我的问题是我在转换中损失了一个小时。我怀疑它是由于时区造成的,但据我所知,传递的日期和正在使用的日历都是GMT。
例如,如果我传入以下NSDate对象(这是[NSDate description]的日志)...
2010-08-02 08:00:00 +0100
我希望我能获得8小时和0分钟,但实际上我的工作时间是7小时。
我的系统时间是GMT,因此上面的NSDate目前是英国夏令时的+0100。
答案 0 :(得分:15)
另请注意,NSDate
对象始终根据GMT显示时间,而您从该日期开始提取的组件会被timeZoneWithName
部分更改。
示例:
NSDate *today = [NSDate date];
NSLog(@"Today's date: %@",today);
unsigned hourAndMinuteFlags = NSHourCalendarUnit | NSMinuteCalendarUnit;
NSCalendar* calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
[calendar setTimeZone:[NSTimeZone timeZoneWithName:@"GMT"]];
NSDateComponents* travelDateTimeComponents = [calendar components:hourAndMinuteFlags fromDate:today];
NSString* hours = [NSString stringWithFormat:@"%02i", [travelDateTimeComponents hour]];
NSString* minutes = [NSString stringWithFormat:@"%02i", [travelDateTimeComponents minute]];
NSLog(@"Calendar: %@",calendar);
NSLog(@"Travel Components: %@",travelDateTimeComponents);
NSLog(@"Hours: %@",hours);
NSLog(@"Minutes: %@",minutes);
控制台输出:
[Session started at 2011-01-23 12:59:17 -0700.]
2011-01-23 12:59:19.755 testttt[5697:207] Today's date: 2011-01-23 19:59:19 +0000
2011-01-23 12:59:19.756 testttt[5697:207] Calendar: <__NSCFCalendar: 0x4b2ca70>
2011-01-23 12:59:19.757 testttt[5697:207] Travel Components: <NSDateComponents: 0x4b2de20>
2011-01-23 12:59:19.757 testttt[5697:207] Hours: 19
2011-01-23 12:59:19.758 testttt[5697:207] Minutes: 59
现在,如果我们改变时区......
NSDate *today = [NSDate date];
NSLog(@"Today's date: %@",today);
unsigned hourAndMinuteFlags = NSHourCalendarUnit | NSMinuteCalendarUnit;
NSCalendar* calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
[calendar setTimeZone:[NSTimeZone timeZoneWithName:@"MST"]];
NSDateComponents* travelDateTimeComponents = [calendar components:hourAndMinuteFlags fromDate:today];
NSString* hours = [NSString stringWithFormat:@"%02i", [travelDateTimeComponents hour]];
NSString* minutes = [NSString stringWithFormat:@"%02i", [travelDateTimeComponents minute]];
NSLog(@"Calendar: %@",calendar);
NSLog(@"Travel Components: %@",travelDateTimeComponents);
NSLog(@"Hours: %@",hours);
NSLog(@"Minutes: %@",minutes);
输出:
2011-01-23 13:05:29.896 testttt[5723:207] Today's date: 2011-01-23 20:05:29 +0000
2011-01-23 13:05:29.897 testttt[5723:207] Calendar: <__NSCFCalendar: 0x4e10020>
2011-01-23 13:05:29.897 testttt[5723:207] Travel Components: <NSDateComponents: 0x4e0f6d0>
2011-01-23 13:05:29.898 testttt[5723:207] Hours: 13
2011-01-23 13:05:29.898 testttt[5723:207] Minutes: 05
注意当地时间和分钟如何变化,但“今天的日期:”部分仍然反映了GMT。如果你问我,有点误导程序员。
答案 1 :(得分:5)
2010-08-02 08:00:00 +0100
等于2010-08-02 07:00:00 GMT
,因此您需要7小时。
答案 2 :(得分:3)
我同意aqua。这是非常误导,并让我几天撞到屏幕上。它的工作方式如下:[NSDate date]始终返回当前日期。所以在上面的例子中它将是2010-08-02 08:00:00。当我们转换为NSDateComponents时,实际时间会丢失并转换为一组不再占用时区的整数(小时,年等)。
当转换回NSDate对象时,它将采用年,月,日等的值并相对于GMT给你,因此丢失了一小时。这就是它在框架中决定的方式。我的工作如下:
+(NSDateComponents *)getComponentFromDate:(NSDate *)date {
NSCalendar * gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
unsigned unitFlags = NSYearCalendarUnit | NSMonthCalendarUnit | NSWeekdayCalendarUnit | NSDayCalendarUnit;
NSDateComponents* components = [gregorian components:unitFlags fromDate:date];
NSTimeZone* timeZone = [NSTimeZone localTimeZone];
if(timeZone.isDaylightSavingTime) components.hour = ((int)timeZone.daylightSavingTimeOffset/3600);
[gregorian release];
return components;
}
这将给我一个四舍五入到当天的组件的“更正”版本,当传递到日历以检索日期时,将始终设置为作为参数传递的日期的00:00:00。