我正在尝试根据其键创建嵌套数组。 如果简化任务,也可以更改原始数组中的键格式。
来自:
$arr = [
'player' => [
'name' => 'Joe'
, 'lastName' => 'Snow'
]
,'team' => [
'name'=> 'Stars'
,'picture' => [
'name' => 'Joe Snow Profile'
, 'file' =>'xxx.jpg'
]
],
];
要:
<span ng-bind-html="myCtrl.textToTranslate|translate"></span>
答案 0 :(得分:6)
这是我的看法 它应该能够处理任意深度
function unflatten($arr) {
$result = array();
foreach($arr as $key => $value) {
$keys = explode(".", $key); //potentially other separator
$lastKey = array_pop($keys);
$node = &$result;
foreach($keys as $k) {
if (!array_key_exists($k, $node))
$node[$k] = array();
$node = &$node[$k];
}
$node[$lastKey] = $value;
}
return $result;
}
答案 1 :(得分:1)
迭代和递归的组合。可以简化为迭代。
$array = [
'player.name' => 'Joe',
'player.lastName' => 'Snow',
'team.name' => 'Stars',
'team.picture.name' => 'Joe Snow Profile',
'team.picture.file' => 'xxx.jpg'
];
$newArray = array ();
foreach($array as $key=> $value) {
$temp = array ();
$keys = array_reverse (explode('.', $key));
$temp[$keys[0]] = $value;
for ($i = 1; $i < count($keys); $i++) {
$temp[$keys[$i]] = $temp;
unset ($temp [$keys [$i -1]]);
}
$newArray = array_merge_recursive($newArray,$temp);
}
var_dump($newArray );
答案 2 :(得分:1)
我收到这个问题作为测试,这是我的答案:
<?php
function buildArray(&$newArray, $keys, $value)
{
if (sizeof($keys) == 0) {
return $value;
} else {
$key = array_shift($keys);
if (isset($newArray[$key])) {
$value = buildArray($newArray[$key], $keys, $value);
if (is_array($value)) {
$newArray[$key] += $value;
} else {
$newArray[$key] = $value;
}
$arr = $newArray;
} else {
$arr[$key] = buildArray($newArray, $keys, $value);
}
}
return $arr;
}
$arr = [
'player.name' => 'Joe',
'player.lastName' => 'Snow',
'team.name' => 'Stars',
'team.picture.name' => 'Joe Snow Profile',
'team.picture.file' => 'xxx.jpg',
];
$newArray = [];
foreach ($arr as $key => $value) {
$explodedKey = explode(".", $key);
$temp = buildArray($newArray, $explodedKey, $value);
$newArray = array_merge($temp, $newArray);
}
print_r($newArray);
?>
答案 3 :(得分:0)
你可以这样做
$newArr = [];
for ($arr as $key => $val) {
$tmp = explode ('.', $key);
if (!array_key_exists ($tmp [0], $newArray){
$newArray [$tmp [0]] = [];
}
$newArray [$tmp [0]][$tmp [1]] = $val;
}
修改强> 该死的没有看到团队中的第三级 不是非常通用但应该适用于第三级;)
$newArr = [];
for ($arr as $key => $val) {
$tmp = explode ('.', $key);
if (!array_key_exists ($tmp [0], $newArray){
$newArray [$tmp [0]] = [];
}
if (count($tmp) > 2){
if (!array_key_exists ($tmp [1], $newArray[$tmp [0]]){
$newArray [$tmp [0]][$tmp[1]] = [];
}
$newArray [$tmp [0]][$tmp [1]][$tmp [2]] = $val;
} else {
$newArray [$tmp [0]][$tmp [1]] = $val;
}
}
答案 4 :(得分:0)
我认为您可以使用类似的方法将2d数组转换为嵌套树。但是你必须和parent_id一起玩