我尝试捕获异常,但我仍然得到"致命错误:未捕获异常' GuzzleHttp \ Exception \ ClientException'消息'客户端错误:404'在C:\ OS \ OpenServer \ domains \ kinopoisk \ parser \ php \ vendor \ guzzlehttp \ guzzle \ src \ Middleware.php:69"
<?php
ini_set('display_errors', 'on');
error_reporting(E_ALL);
set_time_limit(0);
require "vendor/autoload.php";
use GuzzleHttp\Client;
use Psr\Http\Message\ResponseInterface;
use GuzzleHttp\Exception\RequestException;
use GuzzleHttp\Exception\ClientException;
$filmsUrl = [297, 298];
$urlIterator = new ArrayObject($filmsUrl);
$client = new Client([
'base_uri' => 'http://example.com',
'cookies' => true,
]);
foreach ($urlIterator->getIterator() as $key => $value) {
try {
$promise = $client->requestAsync('GET', 'post/' . $value, [
'proxy' => [
'http' => 'tcp://216.190.97.3:3128'
]
]);
$promise->then(
function (ResponseInterface $res) {
echo $res->getStatusCode() . "\n";
},
function (RequestException $e) {
echo $e->getMessage() . "\n";
echo $e->getRequest()->getMethod();
}
);
} catch (ClientException $e) {
echo $e->getMessage() . "\n";
echo $e->getRequest()->getMethod();
}
}
$promise->wait();
我的代码有什么问题?
答案 0 :(得分:4)
我不确定,但你只是在这里捕捉ClientException
。尝试抓住RequestException
。查看Middleware.php:69
中使用的异常类中的代码,但是如果要捕获所有异常,那么您需要选择最抽象的异常类,它应该是
RuntimeException
或GuzzleException
。
尝试这样的事情:
try {
// your code here
} catch (RuntimeException $e) {
// catches all kinds of RuntimeExceptions
if ($e instanceof ClientException) {
// catch your ClientExceptions
} else if ($e instanceof RequestException) {
// catch your RequestExceptions
}
}
或者您可以尝试以下方法
try {
// your code here
} catch (ClientException $e) {
// catches all ClientExceptions
} catch (RequestException $e) {
// catches all RequestExceptions
}
希望有所帮助。
答案 1 :(得分:0)
<?php
//some code
try {
$promise->wait();
} catch (RequestException $e) {
echo $e->getMessage();
}
在guzzlehttp requestasync方法中,HTTP请求是在调用wait方法时发起的,而不是在调用requestasync方法或then方法时发起的。所以需要在wait方法中加入try catch