Question

def read_dict(file_name):
    f=open(file_name,'r')
    dict_rap={}
    for key, val in csv.reader(f):
        dict_rap[key]=str(val)
    f.close()
    return(dict_rap)
test_dict = {'wassup':['Hi','Hello'],'get up through':['to leave','to exit'],
             'its on with you':['good bye','have a nice day'],'bet':['ok','alright'],'ight':['ok','yes'],
              'whip':['car','vechile'],'lit':['fun','festive'],'guap':['money','currency'],'finesse':['to get desired results by anymeans','to trick someone'],
             'jugg':['how you makemoney','modern term for hustle'],'1111':['www'] }

 
    Traceback (most recent call last):
     File "C:\Users\C2C\Desktop\rosetta_stone.py", line 97, in 
      reformed_dict = read_dict(file_name)#,test_dict)
      File "C:\Users\C2C\Desktop\rosetta_stone.py", line 63, in read_dict
       for key, val in csv.reader(f):
      ValueError: too many values to unpack (expected 2)

Answer 1

我担心csv.reader(f)没有返回你期望它返回的内容。我不确切知道你的.csv文件是怎么样的，但我怀疑它会直接返回你试图放入字典的两个值。

假设.csv的前3行看起来像这样：

wassup,hi,hello
get up through,to leave,to exit
its on you,good bye,have a nice day

获取.cvs并迭代每一行的更好方法可能是：

...
my_csv = csv.reader(f)
for row in my_csv:
    # row is a list with all the values you have in one line in the .csv
    if len(row) > 1:
        key = row[0] # for the 1st line the value is the string: 'wassup'
        values = row[1:] # here for the first line you get the list: ['hi', 'hello']
        # ... and so on

Answer 2

来自var loginPageView = Backbone.View.extend({ events :{ "click #login" : "login", "change input[type=radio]":"changeLanguage" }, initialize : function() { //Some Code }, render: function() { this.template = _.template(loginTpl); $(this.el).html(this.template); return this; }, login:function(){ console.log("Login Clicked"); router.navigate('home', {trigger: false, replace: false}); }, changeLanguage:function(){ //console.log("change lang"); if(i18n.currentLocal == 'en'){ i18n.currentLocal='fr'; this.render(); $("#month2").attr('checked',true); }else { if(i18n.currentLocal == 'fr'){ i18n.currentLocal='en'; this.render(); } } } }); return loginPageView;文档......

csv

我想这很自我解释......

我认为该列表的每一行都是您期待的字典。因此，您的In [2]: csv.reader?? Docstring: csv_reader = reader(iterable [, dialect='excel'] [optional keyword args]) for row in csv_reader: process(row) ...... ...... The returned object is an iterator. Each iteration returns a row处理代码应该进入迭代，迭代将遍历dict

返回的胖列表

Answer 3

据说csv.reader（f）只会产生一件你想要处理的东西（key和val）。

假设您使用的是标准csv模块，那么您只能获得一个项目的列表。如果您希望输入有两个项目，那么您可能需要使用不同的分隔符。例如，如果您的输入具有半冒号而不是逗号：

csv.reader(f, delimiter=";")

打开太多值（预期2）

3 个答案: