Question

如果答案不是y或n，为什么当我尝试运行时，代码不会再次询问用户？

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{
    char answer;
    cout << "Do you like cheese?" << endl;
    cin >> answer;

    if ( answer != 'y' && answer != 'n' ) {
        cout << endl << "Wrong answer, Try again: ";
        cin >> answer;
    }
    return 0;
}

我知道它不是循环，但我的其他代码似乎工作正常。如果得分小于0，它将继续要求一个数字。为什么这个代码不会起作用呢？

cout << "Enter the number of goals that were scored: ";
cin >> scored;

if ( scored < 0 ) {
    cout << "Error: the number of goals must be greater than 0. Try again: ";
    cin >> scored;
}

Answer 1

在if声明中更改if，并将其替换为while。

while ( answer != 'y' && answer != 'n' ) {
    cout << endl << "Wrong answer, Try again: ";
    cin >> answer;
}

然后将下面的代码放在下面：

//Do what you want with 'answer' here...

Answer 2

#include <iostream>
using namespace std;
int main(){
    char answer;
    cout<<"do you like cheese?"<<endl;
    cin>>answer;
    while((answer!='y'&&answer!='n')){
        cout<<"do you like cheese?"<<endl;
        cin>>answer;
    }
return 0;
}

C加上不会循环

2 个答案: