从ForeignKeyField填充时，更改Django ModelChoiceField中的键

Question

我一直在看这篇文章：how to populate dropdown list in Django from a foreignkey model我正在寻找下一步。这是我的模特：

class customer(models.Model):
    custid = models.AutoField(primary_key=True)
    name = models.CharField(max_length=30)
    email = models.EmailField(max_length=245)
    address = models.CharField(max_length=50)
    state = models.CharField(max_length=2)
    zip = models.CharField(max_length=5)
    phone = models.CharField(max_length=13)

class job(models.Model):
    jobid = models.AutoField(primary_key=True)
    custid = models.ForeignKey('customer')
    description = models.TextField()
    address = models.CharField(max_length=50)
    state = models.CharField(max_length=2)
    zip = models.CharField(max_length=5)

这是我的表格：

class JobForm(ModelForm):
    class Meta:
        model = job
        exclude = ['jobid']

以下是我对此页面的看法：

def receivables(request):
    """Renders the receivables page."""
    assert isinstance(request, HttpRequest)
    job_list = job.objects.all()
    cus_list = customer.objects.all()

    if request.method == 'POST':
        jobForm = JobForm(request.POST)
        if jobForm.is_valid():
            jobForm.save()
            return HttpResponseRedirect('/receivables/')
    else:
        jobForm = JobForm() 

    context = RequestContext(request, {
        'customers':cus_list,
        'jobs':job_list,
        'job_form':jobForm
        })
    return render(
        request,
        'app/receivables.html',
        context
    )

我的问题是，每当我在模板中调用{{ jobs.custid }}时，我都会看到一个如下所示的下拉框：

我希望使用客户视图中的'name'字段填充这些选项。有什么想法吗？

Answer 1

为您的客户模型添加__str__（对于Python2.x __unicode__）方法：

class customer(models.Model):
    custid = models.AutoField(primary_key=True)
    name = models.CharField(max_length=30)
    email = models.EmailField(max_length=245)
    address = models.CharField(max_length=50)
    state = models.CharField(max_length=2)
    zip = models.CharField(max_length=5)
    phone = models.CharField(max_length=13)

    def __str__(self):  # __unicode__ for python2.x
        return self.name