Question

这是我当前的代码，正如您所看到的，其中很大一部分是重复发生的代码，只需对其进行一些调整，例如输入，输出名称和链接。有什么方法可以将两个相似的代码块组合在一起，但仍然得到相同的结果。

我将在未来做一些类似纯度拳头和后退者的事情。

        if (userinput.Contains("pf")||userinput.Contains("all"))
        {

            //PURITY FIST
            HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://steamcommunity.com/market/priceoverview/?currency=3&appid=440&market_hash_name=Genuine%20Purity%20Fist");
            HttpWebResponse response = (HttpWebResponse)request.GetResponse();
            StreamReader stream = new StreamReader(response.GetResponseStream());
            var final_response = stream.ReadToEnd();


            // Converts the unicode to string correctValue.
            string correctValue = "Euro";
            StringBuilder sb = new StringBuilder(final_response);
            if (sb.ToString().Contains("\\u20ac"))
            {
                sb.Replace("\\u20ac", correctValue);
            }

            dynamic items = JObject.Parse(sb.ToString());

            bool success = items.success;
            string lowest = items.lowest_price;
            string volume = items.volume;
            string median = items.median_price;

            // Create a test object of RootObject class
            RootObject r = new RootObject(success, lowest, volume, median);

            // Calculation example
            double num1 = double.Parse(r.FixComma(r.lowest_price, correctValue), CultureInfo.InvariantCulture);
            double num2 = double.Parse(r.FixComma(r.median_price, correctValue), CultureInfo.InvariantCulture);



            Console.WriteLine("Genuine Purity Fist");

            if (success == true)
            {
                if (num1 >= num2)
                {
                    Console.WriteLine(r.median_price);
                    Console.WriteLine();
                    if (userinput.Contains("pf"))
                    {
                        Console.ReadKey();
                    }
                }

                else
                {
                    Console.WriteLine(r.lowest_price);
                    Console.WriteLine();
                }
            }
        }

    if (userinput.Contains("bb")||userinput.Contains("all"))
    {
        //BACKBITER'S BILLYCOCK
        HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://steamcommunity.com/market/priceoverview/?currency=3&appid=440&market_hash_name=Genuine%20Backbiter%27s%20Billycock");
        HttpWebResponse response = (HttpWebResponse)request.GetResponse();
        StreamReader stream = new StreamReader(response.GetResponseStream());
        var final_response = stream.ReadToEnd();


        // Converts the unicode to string correctValue.
        string correctValue = "Euro";
        StringBuilder sb = new StringBuilder(final_response);
        if (sb.ToString().Contains("\\u20ac"))
        {
            sb.Replace("\\u20ac", correctValue);
        }

        dynamic items = JObject.Parse(sb.ToString());

        bool success = items.success;
        string lowest = items.lowest_price;
        string volume = items.volume;
        string median = items.median_price;

        // Create a test object of RootObject class
        RootObject r = new RootObject(success, lowest, volume, median);

        // Calculation example
        double num1 = double.Parse(r.FixComma(r.lowest_price, correctValue), CultureInfo.InvariantCulture);
        double num2 = double.Parse(r.FixComma(r.median_price, correctValue), CultureInfo.InvariantCulture);



        Console.WriteLine("Backbiter's Billycock");

        if (success == true)
        {
            if (num1 >= num2)
            {
                Console.WriteLine(r.median_price);
                Console.WriteLine();
                Console.ReadKey();
            }

            else
            {
                Console.WriteLine(r.lowest_price);
                Console.WriteLine();
                if (userinput.Contains("bb"))
                {
                    Console.ReadKey();
                }
            }
        }
    }

            else
            {
                Console.WriteLine("Item not found!");
                Main(args);
            }
        }
    }
}





public class RootObject
{
    public bool success { get; set; }
    public string lowest_price { get; set; }
    public string volume { get; set; }
    public string median_price { get; set; }

    public RootObject(bool success, string lowest_price, string volume, string median_price)
    {
        this.success = success;
        this.lowest_price = lowest_price;
        this.volume = volume;
        this.median_price = median_price;
    }

    public string FixComma(string value, string currency)
    {
        string correctValue = ".";
        string correctValue2 = "";
        StringBuilder sb = new StringBuilder(value);
        if (sb.ToString().Contains(","))
        {
            sb.Replace(",", correctValue);
        }
        if (sb.ToString().Contains(currency))
        {
            sb.Replace(currency, correctValue2);
        }
        return sb.ToString();
    }
}

Answer 1

两个if语句之间存在一些差异：

if子句的字符串（＆＃34; pf＆＃34;或＆＃34; bb＆＃34;）
URL的字符串（以＆＃34结尾; Purity％20Fist＆＃34;或＆＃34; Backbiter％27s％20Billycock＆＃34;）
Console.WriteLine的字符串（＆＃34;真正的纯净拳头＆＃34;或者＃34; Backbiter＆＃B; Billycock＆＃34;）
Console.ReadKey的条件（num1 >= num2和userinput.Contains("pf")或num1 >= num2或userinput.Contains("bb")）

不确定为什么存在第四个差异，为什么案件如此奇怪地不同，但我想你知道。无论如何，你可以创建一个将这些差异作为参数的函数，如下所示：DoWork(bool containsSpecific, string urlPathEnding, string itemTitle, bool useOrInsteadOfAnd)。只需调用此函数两次：

DoWork(userinput.Contains("pf"), "Purity%20Fist", "Genuine Purity Fist", false);
DoWork(userinput.Contains("bb"), "Backbiter%27s%20Billycock", "Backbiter's Billycock", true);

最后一个参数在if (success == true)块的末尾使用（顺便说一下，您应该删除== true部分，因为它是多余的），但在if (num1 >= num2) .. else ..部分之外：

    if (success == true)
    {
        if (num1 >= num2)
           ...
        else
           ...

        if ((!useOrInsteadOfAnd && num1 >= num2 && containsSpecific) ||
           (useOrInsteadOfAnd && (num1 >= num2 || containsSpecific)))
        {
            Console.ReadKey();
        }
    }

如何使重复出现的代码程序更有效？

1 个答案: