如何制作我的PHP代码,在html表中显示?

时间:2015-11-21 12:17:10

标签: php html mysql css

我有一个PHP代码,可以显示SQL数据库中的名称和编号。 我有一个带有Name和Number列的html表。我希望我的SQL数据库中的名称和编号显示在HTML表格中。

PHP代码

<?php
$servername = "localhost";
$username = "what7aba_wc";
$password = "This is my Password";
$dbname = "what7aba_wc";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT name, number FROM WC";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
        echo "Name" . $row["name"]. "-Number" . $row["number"]. "<br>";
    }
} else {
    echo "0 results";
}
$conn->close();
?>

HTML表格

  <table id="table" class="table table-hover table-mc-light-blue">
      <thead>
        <tr>
          <th>Name</th>
          <th>Link</th>
        </tr>
      </thead>
      <tbody>
        <tr>
          <td data-title="Name">Its a Name</td>
          <td data-title="Number">

        </tr>
        <tr>
          <td data-title="Name">Its a Name</td>
          <td data-title="Number">

        </tr>
      </tbody>
    </table>

如果这不可能发生。任何人都告诉我如何为上面给出的PHP文件制作CSS。

更新:

我试过这个。

<?php
$servername = "localhost";
$username = "what7aba_wc";
$password = "My Password";
$dbname = "what7aba_wc";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT name, number FROM WC";
$result = $conn->query($sql);

?>
  <h1>WhatsCast List</h1>
  <h2>Table of my other Material Design works (list was updated 08.2015)</h2>

  <div class="table-responsive-vertical shadow-z-1">
  <table id="table" class="table table-hover table-mc-light-blue">
      <thead>
        <tr>
          <th>Name</th>
          <th>Link</th>
        </tr>
      </thead>
      <tbody>
        <tr>
          <td data-title="Name"><p><?php echo $row["name"] ?><p></td>
          <td data-title="Number"><p><?php echo $row["number"] ?></p></td>
         </tr>

      </tbody>
    </table>
  </div>

</div>

1 个答案:

答案 0 :(得分:2)

HTML

System.Configuration