Oracle特定时间戳格式'DD-MON-RR HH.MI.SSXFF AM'

时间:2015-11-21 12:01:08

标签: database oracle oracle11g database-administration nls-lang

我遇到了Oracle 11g特定时间戳格式的问题。

这就是我所拥有的: select to_timestamp('21-OCT-15 08.24.30.000000000 PM','DD-MON-RR HH.MI.SSXFF AM') from dual;

来自数据库的回复:ORA-01855: AM/A.M. or PM/P.M. required 01855. 00000 - "AM/A.M. or PM/P.M. required"

我还尝试用几个命令改变会话设置,但仍然没有。

alter session set NLS_LANGUAGE='ENGLISH';
alter session set NLS_DATE_LANGUAGE='ENGLISH';
alter session set NLS_TIMESTAMP_FORMAT = 'DD-MON-RR HH.MI.SSXFF AM';
alter session set NLS_TIMESTAMP_TZ_FORMAT='DD-MON-RR HH.MI.SSXFF AM';

我无法在SELECT语句中更改时间戳格式,需要保持原样。我想问题出在会话设置中。

有人在oracle数据库管理方面有经验可以提出建议,我会尽力。我知道有几个类似的帖子,但我找不到解决方案。感谢

以下是我的会话设置。

select * from nls_session_parameters;

Session Parameters

4 个答案:

答案 0 :(得分:5)

核心问题是,在会话级别,您有nls_numeric_characters=',.'而您的时间戳字符串包含点(.),而不是秒 - 从 - 微秒分隔符。

to_timestamp()函数可以接受第三个参数来覆盖NLS设置。这是一个小型演示...

Connected to Oracle Database 12c Enterprise Edition Release 12.1.0.2.0 
Connected as ******@******

--- This is how it behaves in your database (with "," as the decimals separator) ...

SQL> alter session set nls_numeric_characters = ',.';

Session altered

SQL> select to_timestamp('21-OCT-15 08.24.30.000000000 PM','DD-MON-RR HH.MI.SSXFF AM') as xx from dual;

select to_timestamp('21-OCT-15 08.24.30.000000000 PM','DD-MON-RR HH.MI.SSXFF AM') as xx from dual

ORA-01855: AM/A.M. or PM/P.M. required

--- This is how it behaves in my database (with "." as the decimals separator) ...

SQL> alter session set nls_numeric_characters = '. ';

Session altered

SQL> select to_timestamp('21-OCT-15 08.24.30.000000000 PM','DD-MON-RR HH.MI.SSXFF AM') as xx from dual;

XX
-------------------------------------------------
21.10.15 20:24:30.000000000

--- Now back to your database settings and let's make the conversion NLS-settings-indepenent ...

SQL> alter session set nls_numeric_characters = ',.';

Session altered

SQL> select to_timestamp('21-OCT-15 08.24.30.000000000 PM','DD-MON-RR HH.MI.SSXFF AM', 'nls_numeric_characters = ''. ''') as xx from dual;

XX
-------------------------------------------------
21.10.15 20:24:30,000000000

SQL> 

请注意第三个SELECT中to_timestamp()函数的第三个参数。除了所有其他正确答案之外,这也是你能做的。

答案 1 :(得分:1)

备份您的NLS设置并运行它们。

    ALTER SESSION SET NLS_DATE_FORMAT='DD-MON-RRRR HH24:MI:SS';
    ALTER SESSION SET NLS_DATE_LANGUAGE='AMERICAN';
    ALTER SESSION SET NLS_TIME_FORMAT='HH.MI.SSXFF AM';
    ALTER SESSION SET NLS_TIMESTAMP_FORMAT='DD-MON-RR HH.MI.SSXFF AM';
    ALTER SESSION SET NLS_TIME_TZ_FORMAT='HH.MI.SSXFF AM TZR';
    ALTER SESSION SET NLS_TIMESTAMP_TZ_FORMAT='DD-MON-RRRR HH.MI.SSXFF AM TZR';

然后再次运行SQL语句。

答案 2 :(得分:0)

最后,我在之前的列表中添加了Territory更改了会话属性,以使其适用于我。感谢

ALTER SESSION SET NLS_TERRITORY=AMERICA;
ALTER SESSION SET NLS_DATE_LANGUAGE='AMERICAN';
ALTER SESSION SET NLS_TIME_FORMAT='HH.MI.SSXFF AM';
ALTER SESSION SET NLS_TIMESTAMP_FORMAT='DD-MON-RR HH.MI.SSXFF AM';
ALTER SESSION SET NLS_TIMESTAMP_TZ_FORMAT='DD-MON-RRRR HH.MI.SSXFF AM TZR';
ALTER SESSION SET NLS_TIME_TZ_FORMAT='HH.MI.SSXFF AM TZR';

答案 3 :(得分:-1)

试试这个:SELECT TO_CHAR(TO_TIMESTAMP(**'2015-11-21-13:03:07.04776'**),'DD-MON-RR HH.MI.SSXFF AM') FROM DUAL;引号之间的时间戳格式应与此查询的结果相同:SELECT TO_CHAR(LOCALTIMESTAMP) FROM DUAL