Question

我正在创建一个包含图片库的Android应用程序。但是我在尝试从我的数据库中获取图像时遇到了困难。我保存了我的图像的路径，并试图将其保存到json然后解析它到我的机器人。这是我的代码：

photo.php

  <?php

define('HOST','');
define('USER','');
define('PASS','');
define('DB','');
$con = mysqli_connect(HOST,USER,PASS,DB);

// query the application data
$sql = "SELECT image FROM photos";
$result = mysqli_query($con, $sql);

// an array to save the application data
$rows = array();

// iterate to query result and add every rows into array
while($row = mysqli_fetch_array($result)) {
$rows[]=$row;

}

// close the database connection
mysqli_close($con);

// echo the application data in json format
echo json_encode($rows);

?>

FetchImage.java

 public class FetchImage extends Activity {
Button load_img;
ImageView img;
Bitmap bitmap;
ProgressDialog pDialog;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_fecth_image);
    load_img = (Button)findViewById(R.id.load);
    img = (ImageView)findViewById(R.id.img);
    load_img.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View arg0) {
            // TODO Auto-generated method stub
             new LoadImage().execute("http://iguideph-001-site1.btempurl.com/PhotoUpload/uploads/vigan1.jpg");
        }
    });


}
private class LoadImage extends AsyncTask<String, String, Bitmap> {
    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        //pDialog = new ProgressDialog(FetchImage.this);
       // pDialog.setMessage("Loading Image ....");
       // pDialog.show();

    }
     protected Bitmap doInBackground(String... args) {
         try {
               bitmap = BitmapFactory.decodeStream((InputStream)new URL(args[0]).getContent());

        } catch (Exception e) {
              e.printStackTrace();
        }
        return bitmap;
     }

     protected void onPostExecute(Bitmap image) {

         if(image != null){
         img.setImageBitmap(image);
         pDialog.dismiss();

         }else{

         pDialog.dismiss();
         Toast.makeText(FetchImage.this, "Image Does Not exist or Network Error", Toast.LENGTH_SHORT).show();

         }
     }
 }

  }

activity_fetch_image.xml

 <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical"
tools:context=".MainActivity" >

<Button
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_gravity="center"
    android:id="@+id/load"
    android:text="Load Image" />

<ImageView
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_gravity="center"
    android:id="@+id/img"/>

  </LinearLayout>

通过图像路径将图像从mysql数据库获取到android

0 个答案: