Question

我在Alfresco中获得了一个文件，其中包含例如：http://localhost:8080/share/proxy/alfresco/workspace/SpacesStore/c9d187e8-aec5-4177-9587-a5b924e514cd/exemplo.pdf和javascript上的XMLHttpRequest链接，我没有遇到任何问题。但我正试图在JAVA上这样做：

public static byte[] callURL(String myURL) {
        System.out.println("Requeted URL:" + myURL);
        StringBuilder sb = new StringBuilder();
        URLConnection urlConn = null;
        InputStreamReader in = null;
        try {
            URL url = new URL(myURL);

            urlConn = url.openConnection();
            if (urlConn != null)
                urlConn.setReadTimeout(60 * 1000);
            if (urlConn != null && urlConn.getInputStream() != null) {
                in = new InputStreamReader(urlConn.getInputStream(),
                        Charset.defaultCharset());
                BufferedReader bufferedReader = new BufferedReader(in);
                if (bufferedReader != null) {
                    int cp;
                    while ((cp = bufferedReader.read()) != -1) {
                        sb.append((char) cp);
                    }
                    bufferedReader.close();
                }
            }
            in.close();
        } catch (Exception e) {
            throw new RuntimeException("Exception while calling URL:" + myURL, e);
        }
        String sbString = sb.toString();
        System.out.println(sbString);
        byte[] b = sbString.getBytes(StandardCharsets.UTF_8); 
        return b;
    }

但这给了我

401未经授权

。问题是什么？我需要任何身份验证？我该如何解决这个问题？

Answer 1

我解决了！对于可能遇到同样问题的人，请按照tutorial进行操作。您有，包括，如何访问内容。

纯文字

ContentReader reader = contentService.getReader(nodeRef, ContentModel.PROP_CONTENT);
String content = reader.getContentString();

二进制数据：

ContentReader reader = contentService.getReader(nodeRef, ContentModel.PROP_CONTENT);
InputStream originalInputStream = reader.getContentInputStream();
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
final int BUF_SIZE = 1 << 8; //1KiB buffer
byte[] buffer = new byte[BUF_SIZE];
int bytesRead = -1;
while((bytesRead = originalInputStream.read(buffer)) > -1) {
    outputStream.write(buffer, 0, bytesRead);
}
originalInputStream.close();
byte[] binaryData = outputStream.toByteArray();

获取文件（401未经授权） - Alfresco

1 个答案: