Question

我有以下数据：

 $scope.icons = [{
"id": 1,
"bonuses": [
  { "id": 1, "name": "Rob",  "amount": 10, "foreman": 1, "percA": 1, "percB": 0  },
  { "id": 2, "name": "Mark", "amount": 20, "foreman": 1, "percA": 1, "percB": 0  },
]
  }, {
    "id": 2,
"bonuses": [
  { "id": 1, "name": "Rob",  "amount": 11, "foreman": 1, "percA": 1, "percB": 0  },
  { "id": 2, "name": "", "amount": 30, "foreman": 1, "percA": 1, "percB": 0  },
]
  }, {
"id": 3,
"bonuses": [
  { "id": 1, "name": "Rob",  "amount": 10, "foreman": 1, "percA": 1, "percB": 0  },
  { "id": 2, "name": "Kent", "amount": 35, "foreman": 1, "percA": 1, "percB": 0  },
]
}];

控制器内部的这个功能：

$scope.getBonusPeople = function() {

var bonusData = [];

angular.forEach($scope.icons, function(item) {

  angular.forEach(item.bonuses, function(bonusLine) {

    if (bonusData.indexOf(bonusLine) == -1 ) {
      bonusData.push(bonusLine);
    }

  })
});

return $scope.bonusPeople = bonusData;
}

这就是结果：

Rob - 10
Mark - 20
Rob - 11
- 30
Rob - 10
Kent - 35

我试图找到bonuses.name有值的行。

结果应该是

Rob - 10
Mark - 20
Rob - 11
Rob - 10
Kent - 35

我该怎么做。

这里有一个傻瓜http://plnkr.co/edit/wZpr0nerqti4L2Yg37iT?p=preview

Answer 1

您需要添加一项检查以查看name是否为空字符串。请参阅下面的代码段。

╔═════╦════════╦══════════════╗
║ ID  ║ Desc1  ║ BALANCE_DATE ║
╠═════╬════════╬══════════════╣
║ ID1 ║ Desc 3 ║ 2015-10-22   ║
║ ID2 ║ Desc 3 ║ 2015-09-28   ║
║ ID3 ║ Desc 1 ║ 2015-10-18   ║
╚═════╩════════╩══════════════╝

Answer 2

检查名称是否有值。如果是，请继续执行当前逻辑：

angular.forEach($scope.icons, function(item) {
  angular.forEach(item.bonuses, function(bonusLine) {
    if(bonusLine.name!=='') {
        if (bonusData.indexOf(bonusLine) == -1 ) {
          bonusData.push(bonusLine);
        }
    }
  })
});

普兰克：http://plnkr.co/edit/E9bXzn8Jt2B8yJ3IU33s?p=preview

具有空值的角度过滤器对象

2 个答案: