Ruby使用each_with_index

Question

我希望这种方法遍历名称.... url(r'^users/$', view=UsersView.as_view(), name='users_index'), url(r'^users/(?P<user_id>\d+)/$', view=UsersView.as_view(), name='users_user'), ... 数组中的每个项目，并使用katz_deli来显示名称及其索引。但是，输出只是数组中带有索引的第一个名称。

我的代码：

puts

我希望我的输出为def line (katz_deli) if katz_deli.count > 1 katz_deli.each_with_index {|name, index| puts "The line is currently: #{index +1}. #{name}" } else puts "The line is currently empty." end end 但我得到"The line is currently: 1. Logan 2. Avi 3. Spencer"谢谢！

Answer 1

您可以首先构建输出字符串，并在准备就绪后构建puts：

input = ["Logan", "Avi", "Spencer"]

def line (katz_deli)
  if katz_deli.count > 1
    output = "The line is currently:"
    katz_deli.each_with_index do |name, index|
      output << " #{index +1}. #{name}"
    end
    puts output
  else
    puts "The line is currently empty."
  end
end

line(input)

Answer 2

def line (katz_deli)
  if katz_deli.count > 1
    print "The line is currently:"
    katz_deli.each_with_index {|name, index|  print " #{index +1}. #{name}" }
  else
    puts "The line is currently empty."
  end
end